Which statement best describes the concept of Einstein’s equation E = mc2?

NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a

jeyben [28]

Answer:

λ₁ = 2.50 10⁻² m, λ₂ = 1.66 10⁻² m

Explanation:

Microwave communication is very efficient because it does not have atmospheric interference, for which it is widely used and has been regulated to avoid interference, the ku band is in the range between 12 and 18 GHz.

Let's calculate the wavelength for the two extreme frequencies of this band

wavelength and frequency are related

c = λ f

λ = c / f

f₁ = 12 GHz = 12 10⁹ Hz

λ₁ = 3 10⁸ /12 10⁹

λ₁ = 2.50 10⁻² m

f₂ = 18 GHz = 18 10⁹ Hz

λ₂ = 3 10⁸ /18 10⁹

λ₂ = 1.66 10⁻² m

Unfortunately in your exercise the specific frequency is not fired, for significant figures they must be the same number as the figures of the frequency, in general the frequency has 3 or 4 significant figures

8 0

3 years ago

Why is Saturn almost as big as Jupiter, despite its smaller mass?

gulaghasi [49]

Answer:

c. Jupiter's greater mass compresses it more, thus increasing its density.

Explanation:

The mass of Jupiter is greater in its interior, this mass compresses Jupiter to some extent. Thus, its density is increased. Now, more mass is compressed in the lesser volume. Hence, its size does not increase enormously. On the other hand the mass of Saturn is lesser and also density lower. this gives Saturn a reasonably higher volume.

Hence, option C is correct.

6 0

3 years ago

A magnesium surface has a work function of 2.65 eV. Electromagnetic waves with a wavelength of 280 nm strike the surface and eje

Neko [114]

Answer:

Explanation:

Energy of radiation in eV = 1237.5/280 = 4.42 eV.

Work function = 2.65 eV.

Maximum kinetic energy = 4.42 - 2.65 = 1.77 eV.

8 0

4 years ago

X-rays cannot pass through Earth's atmosphere. Which of these is the best location to place a telescope used to observe x-rays f

Amiraneli [1.4K]

Mountains, tops of buildings, and high-flying aircraft are all part of Earth's atmosphere, no matter how high they are. On the other hand, space doesn't belong to our atmosphere, it is outside of it. Having this in mind, the best location to place a telescope used to observe x-rays from stars is in space.

7 0

3 years ago

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A sound system is being set up in a gazebo in a park. It needs to produce music so that everyone can hear it. How much power wou

Agata [3.3K]

Answer:

Power of the speakers = 1.57 $\times 10^{-6} W$

Explanation:

There are speakers setup in a park and we have to find the power it would require to have intensity of sound to be $10^{-8} W/m^2$ at a distance of 5 meter.

In one dimension the intensity is constant as the wave travels. In two or three dimensions, however, the intensity decreases as you get further from the source.

Intensity is inversely proportional to the square of the distance from the point of sound production.

Here area = 2 $\times \pi \times r^{2}$

area = 157 $m^{2}$

$Intensity = \frac{Power}{Area}$

$Power = intensity \times area$

Power = $10^{-8} \times 157Power = 1.57 [tex]\times 10^{-6} W$

7 0

3 years ago