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rewona [7]
3 years ago
11

What can iron filings sprinkled on a piece of paper demonstrate? A. the clockwise motion of the magnetic field B. the counter-cl

ockwise motion of the magnetic field C. the pattern of the magnetic field lines D. the distortion of the magnetic fields
Physics
2 answers:
d1i1m1o1n [39]3 years ago
8 0

The answer is C. because the lines will look the same as the earths gravity field (you can look up a graph)

Roman55 [17]3 years ago
4 0

The answer is C. because the lines will look the same as the earths gravity field (you can look up a graph)

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What force does the water exert (in addition to that due to atmospheric pressure) on a submarine window of radius 44.0 cm at a d
Butoxors [25]
Calculate the pressure due to sea water as density*depth.
That is, 
pressure = (1025 kg/m^3)*((9400 m)*(9.8 m/s^2) = 94423000 Pa = 94423 kPa

Atmospheric pressure is  101.3 kPa
Total pressure is  94423 + 101.3 = 94524 kPa (approx)

The area of the window is π(0.44 m)^2 = 0.6082 m^2

The force on the window is
(94524 kPa)*(0.6082 m^2) = 57489.7 kN = 57.5 MN approx
3 0
4 years ago
Which one of the following statements indicates the result of Kepler's astronomical calculations?
garri49 [273]
The correct answer for the question that is being presented above is this one: "<span>c. Planets orbit in elliptical patterns; a planet's orbit covers equal areas in equal amounts of time; planets' orbits are shorter or longer depending on their distance from the Sun."</span>

Here are the following choices:
a. Planets orbit in elliptical patterns; the bigger the planet, the more gravitational pull; a planet's gravitational pull is stronger or weaker depending on its distance from the Sun.

b. A planet's orbit covers equal distances in equal amounts of time; the speed of a planet's orbit depends on its distance from the Sun; the bigger the planet, the slower it moves.

c. Planets orbit in elliptical patterns; a planet's orbit covers equal areas in equal amounts of time; planets' orbits are shorter or longer depending on their distance from the Sun.
5 0
3 years ago
Consider a machine of mass 70 kg mounted to ground through an isolation system of total stiffness 30,000 N&gt;m, with a measured
kvv77 [185]

Answer:

a)0.0229 m

b)0.393 rad

c)1.57

d)707.6 N

e)0.298 m/s

Explanation:

Given:

  • Mass of the machine, m=70 kg
  • Stiffness of the system, k=30000 N/m
  • Damping ratio=0.2
  • Damping force, F=450 N
  • Angular velocity \omega=13\ \rm rad/s

a)We know that the amplitude X at steady state is given by

X=\dfrac{\dfrac{F_0}{m}}{\sqrt{\omega_n^2-\omega^2)^2 +(2\rho \omega_n\omega)^2}}\\

Where

  • \omega_n=\sqrt{\dfrac{k}{m}}\\\\=\sqrt{\dfrac{30000}{70}}\\\\=20.7\ \rm rad/s
  • \omega=13\ \rm rad/s
  • \rho=0.2
  • F_0=450\ \rm N
  • m=70\ \rm kg

X=\dfrac{\dfrac{450}{70}}{\sqrt{20.7^2-13^2)^2 +(2\times 0.2\times20.7\times13)^2}}\\[tex]X=0.0229\ \rm m

b) The phase shift of the motion is given by

\tan\phi=\dfrac{2\rho \omega_n \omega }{\omega_n^2-\omega^2}\\\\\dfrac{2\times0.2\times20.7\times13 }{20.7^2-\13^2}\\\\\phai=0.393\\

c)Transmissibility ratio is given by

T.R.=\sqrt{\dfrac{1+(2\rho r)^2}{(1-r^2)^2+{(2\rho r)^2}}}\\\\T.R.=\sqrt{\dfrac{1+(2\times0.2\times0.628)^2}{(1-0.628^2)^2+{(2\times0.2\times0/628)^2}}}\\\\=1.57

d)The magnitude of the force transmitted to the ground is

F_T=(T.R)\times F_0\\\\=450\times1.57\\\\=707.6\ \rm N

e)The maximum velocity is given by V_{max}

V_{max}=\omega A_0\\\\=13\times 0.0229\\\\=0.298\ \rm m/s

6 0
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borishaifa [10]
Hey, I think someone should help u cause I’m stuck too

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3 years ago
Give an example of unbalanced force?​
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Answer:

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Explanation:

5 0
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