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Sunny_sXe [5.5K]
4 years ago
14

Find the dot product of v=-7i+4j and w=-6+5j

Mathematics
1 answer:
Anna35 [415]4 years ago
6 0
V•w = (-7i +4j)•(-6i +5j) = (-7)×(-6) +4×5 = 42 +20
v•w = 62
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Warmup/Reflection- necessary for attendance
Pepsi [2]

Answer:

x = 7

Step-by-step explanation:

-3 + 2x = 11

(group like terms)

2x = 11 + 3

2x = 14

(divide both sides by 2 to make x stand alone)

2x/2 = 14/2

x = 7

8 0
3 years ago
What is the measure of angle RSL if it is (9x+27)° and angle BSA is (6x+66)°
Shalnov [3]

Answer:

Assume:

(angle) RSB and angle (LSA) = D

and (line) ASR and (line) LSB is striaght then

(9x +27) + D = 180

(6x + 66) + D = 180

9x + D = 153

6x + D = 114

substitute

6x + D = 114

D = 114 - 6 x

9x + (114 - 6x) =153

3x = 39

x = 13

D = 114 - 6(13)

D=36


Step-by-step explanation:


8 0
4 years ago
Read 2 more answers
How many solutions does the following equation have? 10x-1=10x+4
zimovet [89]
  • Your answer is no solution.
  • Because if we transpose 10x to the left hand side with a change in the symbol, then it will become 0.
  • 10x - 1 = 10x +4
  • or, 10x - 10x = 4 + 5
  • or, 0 = 9
  • Hence, the equation has <em><u>no solution</u></em>.

Hope you could get an idea from here.

Doubt clarification - use comment section.

7 0
3 years ago
Read 2 more answers
There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

You scored 1167 on Exam B, s:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0
4 years ago
Determine the sum of the parts 1 3/8 +2/3=
Mumz [18]

2 1/24

Rewriting our equation with parts separated

2/3+1+3/8

Solving the fraction parts

2/3+3/8=?

Find the LCD of 2/3 and 3/8 and rewrite to solve with the equivalent fractions.

LCD = 24

16/24+9/24=25/24

Simplifying the fraction part, 25/24,

25/24=1 1/24

Combining the whole and fraction parts

1+1+1/24=2 1/24

5 0
3 years ago
Read 2 more answers
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