Answer:
The standard deviation of weight for this species of cockroaches is 4.62.
Step-by-step explanation:
Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.
To find : What is the approximate standard deviation of weight for this species of cockroaches?
Solution :
We have given,
Mean 
The sample mean x=55
A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.
i.e. P(X>55)=14%=0.14
The total probability needs to sum up to 1,
The z-score value of 0.86 using z-score table is z=1.08.
Applying z-score formula,
Where, 
is standard deviation
Substitute the values,
The standard deviation of weight for this species of cockroaches is 4.62.
Answer: x = 9/4, y = 7/6
║<span>2x + 3y = 8
</span>║<span>4x - 6y = 2
</span>║4x + 6y = 16
║4x - 6y = 2
Add both equations together:
8x = 18
x = 9/4
Sub x = 9/4 into 2x + 3y = 8
2(9/4) + 3y = 8
9/2 + 3y = 8
3y = 7/2
y = 7/6
Mike biked 10 miles in 1.5 hours. Mila bikes at the same rate too.
Therefore, she will bike x miles in 3.5 hours
(10/1.5) = (x/3.5)
You cross multiply
1.5x = 10 x 3.5
1.5x = 35
x = 35/1.5
x = 23 miles (approximately)
I hope this helps
Step-by-step explanation:
Given the table:
Month f(x) = Number of imports g(x) = Number of exports
January (1) 3 1
February (2) 4 3
March (3) 5 5
April (4) 6 7
From the table, it is clear that:
Number of imports = number of month + 2
so
also
Number of exports = 2(number of month) + 1
so
Therefore, number of imports equals the number of month plus one. i.e. , which is a linear function.
If we compare it with slope-intercept form of the line
Then,
slope = m = 1
y-intercept = 2
Also number of exports equals is also a linear function.
i.e.
Here,
slope = m = 2
y-intercept = -1
y=8x+23
y=x/6-1/2
i believe this is the answer
