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faltersainse [42]
3 years ago
11

A box of pencils costs $3.25 and a box of colored pencils costs $4.65. However, a box of pencils and a box of colored pencils ar

e sold together at $6.50. If Alex wants to buy 6 boxes of pencils and 9 boxes of colored pencils, what is the least amount of money that Alex can pay?
Mathematics
1 answer:
ale4655 [162]3 years ago
3 0

Answer:

the least is 40

Step-by-step explanation:

if u multiply each money amount times the amount they bought you get the awnser

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1. Triangle ABC is similar to triangle JKL.
Fittoniya [83]
1. It's all about pattern matching, as a lot of math is.
Letter A corresponds to letter J, as both are first in the names of their respective triangles.
Letter B corresponds to letter K, as both are second in the triangle names. Likewise, letter C corresponds to letter L, as both are last.

Realizing this, it should not be too much of a stretch to see
   ∠B ⇒ ∠K
   ∠C ⇒ ∠L
   AC ⇒ JL
   BC ⇒ KL

2. Same deal. Match the patterns. Here, you're counting rings in the angle marks.
   1 ⇒ 1, so A ⇒ R
   2 ⇒ 2, so B ⇒ Q
since the figures are reportedly similar, you can continue in the same order to finish.
   ABCD ~ RQPS

3. The marked triangles cannot be similar. There are a number of ways to figure this. Basically, you want the ratios of sides to be the same for any similar triangles.

Here, you can eliminate the marked ones because the short side is too short relative to the others. (The average of the other two sides is double the short side in the similar triangles.)

8 0
3 years ago
Look at the figure below; what additional information do you need to have to determine if segment DE is the midsegment?
77julia77 [94]
1. If you knew that DE = \frac{1}{2}CB
Then you would know it is a mid-segment.

2. If you knew that CD =  DA and BE = EA  (point D and point E are midpoints of their respective segments)

3 0
3 years ago
Can some one check this?
timama [110]
There are i<span>Infinitely many solutions </span>
8 0
3 years ago
A circle is shown. 2 raddi are drawn. A chord connects the points of the radii on the circle to each other to form a triangle. T
iragen [17]

Answer:

(5\pi-11.6)ft^2

Step-by-step explanation:

Given:

Length of radius of circle = 5 feets

Length of perpendicular bisector = 4 feets

To find:

Area of the shaded portion of the circle

Solution:

As OD is perpendicular bisector of AB,

AB=2AD=2(2.9)=5.8\,\,feets

\angle ODA=90^{\circ}

Area of \Delta AOB = 1/2 (base) × (height) = \frac{1}{2}\times 4\times 5.8=11.6  square feets

Area of sector AOBC = \frac{\angle AOB}{360^{\circ}}\pi(r^2)=\frac{72^{\circ}}{360^{\circ}}\pi(5^2)=5\pi  square feets

Here, r denotes radius of circle

So,

Area of shaded portion = Area of sector AOBC - Area of \Delta AOB = (5\pi-11.6)ft^2  

Download pptx
3 0
3 years ago
What’s the correct answer for this?
Anarel [89]
As many girls and boys plays sports
4 0
3 years ago
Read 2 more answers
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