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2 years ago

A game spinner has 8 sections, 3 red, 1 blue, 2 yellow, and 2 green. What is the probability that you will spin a yellow?

Mathematics

1 answer:

GaryK [48]2 years ago

3 0

Answer:

1/4 Percent

Step-by-step explanation:

add all them up and youll get 8 the see the yellow takes up 1/4 percent of the numbers.

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3. On a coordinate grid, the location of a lighthouse is at L, and the location of a buoy is at B. At noon, a ship is at the mid

Tju [1.3M]

Answer:

Step-by-step explanation:

im 50% sure this write dont blame me man

6 0

3 years ago

Abbot Tools is designing a new toolbox. The length of the toolbox will be three times its width, w, and the length of the diagon

Ilia_Sergeevich [38]

The length and width of the toolbox given the diagonal is 45 inches and 15 inches respectively.

<h3>Triangle</h3>

Width of the triangle = w
Length of the triangle = 3w
Diagonal = 30 inches

Hypotenuse ² = opposite ² + adjacent ²

30² = w² + (3w²)

30² = 4w²

900 = 4w²

w² = 900/4

= 225

w = √225

w = 15

Therefore,

Width of the triangle = w

= 15 inches

Length of the triangle = 3w

= 3(15)

= 45 inches

Learn more about triangles:

brainly.com/question/24382052

#SPJ1

5 0

1 year ago

3^x = 27^a+b and a^2-b^2/(a-b)=5 What is x?

Colt1911 [192]

Your answer should be 3x-x+2=4 hope this helps..

4 0

3 years ago

HELP giving brainlest and more points

cupoosta [38]

Answer:

4,000,000,000 meters

Step-by-step explanation:

4 x 10,000,000,000,000 x 0.0001 = 4,000,000,000 meters

4 0

3 years ago

Read 2 more answers

10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the

Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

$H_0: \mu = 0$

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

$H_1: \mu > 0$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

In this problem, the parameters are given as follows:

$\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50$ .

Hence, the test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}$

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by $t^{\ast} = 2.4$ .

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0

1 year ago