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Taya2010 [7]
3 years ago
10

Please help me with this!!!!!!!!!!!!!!

Mathematics
2 answers:
miss Akunina [59]3 years ago
6 0

Answer:

True

Step-by-step explanation:

Its true since it passes the vertical line test. How does the vertical line test work? You put a vertical line through a point and if it has only one point on that specific line it is a function. Note:hope this helps

Maru [420]3 years ago
3 0
True how I learned this in school was put your pencil at one end and if keeps going without touching any of its self then it’s a function.
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\qquad\qquad\huge\underline{{\sf Answer}}

\textbf{Let's see if the sequence is Arithmetic or Geometric :}

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Carlos drew a plan for his garden on a coordinate plane. Rose bushes are located at A(–5, 4), B(3, 4), and C(3, –5)
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Given:

A(-5,4)

B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}

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\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

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For B(3,4) and C(3,-5).

\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}

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