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Leokris [45]
3 years ago
7

Please help with this

Mathematics
1 answer:
katen-ka-za [31]3 years ago
3 0
I think it’s supplementary angle
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= -6(x-7) – 9 =what will the equal to ​
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3 years ago
What are the solutions of the equation x^2 =4? Use of the related function
Dmitry_Shevchenko [17]
Well threw my calculations would be <span><span>  x=  0.0000 - 2.0000 i 
</span><span>  x=  0.0000 + 2.0000 i

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4 0
3 years ago
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Help with this!!plz. Asap
gizmo_the_mogwai [7]
Hey there! :D

So, we know that there are 3 z's and 3 6's. 

3*z= 3z

6*3= 18 

3(z+6) <== equivalent expression 

3z+18 <== equivalent expression

z is by itself. It shouldn't combine. It should stay the same. 6 as a unit is separate from z. 

Choices "B" and "E" are correct.

I hope this helps!
~kaikers
5 0
4 years ago
382 milliliters equals to how many liters
Ivan
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3 0
3 years ago
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Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the
zlopas [31]

Answer:

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}

\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

3 0
3 years ago
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