2x + 3 /12 = 2x/8
⇒ 48x/24 + 6/24 = 6x/24
⇒ (48x+ 6)/24= 6x/24
⇒ 48x+ 6 = 6x
⇒ 48x- 6x= -6
⇒ 42x= -6
⇒ x= -6/42
⇒ x= -1/7
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x=-1/7~</span>
4 times because if you count 10, 20, 30, 40, so it has to be 4
I've attached the complete question.
Answer:
Only participant 1 is not cheating while the rest are cheating.
Because only participant 1 has a z-score that falls within the 95% confidence interval.
Step-by-step explanation:
We are given;
Mean; μ = 3.3
Standard deviation; s = 1
Participant 1: X = 4
Participant 2: X = 6
Participant 3: X = 7
Participant 4: X = 0
Z - score for participant 1:
z = (x - μ)/s
z = (4 - 3.3)/1
z = 0.7
Z-score for participant 2;
z = (6 - 3.3)/1
z = 2.7
Z-score for participant 3;
z = (7 - 3.3)/1
z = 3.7
Z-score for participant 4;
z = (0 - 3.3)/1
z = -3.3
Now from tables, the z-score value for confidence interval of 95% is between -1.96 and 1.96
Now, from all the participants z-score only participant 1 has a z-score that falls within the 95% confidence interval.
Thus, only participant 1 is not cheating while the rest are cheating.
Answer:
They are in A. P so the sum will be 2380