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2 years ago

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Mathematics

1 answer:

olga nikolaevna [1]2 years ago

6 0

Answer:5

Step-by-step explanation:>

Which exponential function is represented by the

graph?

8Hold on, our servers are swamped. Wait for your answer to fully load.

o f(x) = 2( 3 )

O f(x) = {(2Y

o f(x) = {(

(1.1

61,0.25) 17

7605

Of(x) = 2(2)

-5 4 3 2 1

1 2 3 4

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is a diameter of circle K. If tangents to circle K are constructed through points L and J, what relationship would exist between

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The company is building a scale model of the theater's main show tank for an investor's presentation. Each dimension will be mad

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This means the mock-up tank has a volume 216 times smaller than the initial tank.

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3 years ago

Read 2 more answers

A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function

dexar [7]

Here's our equation.

$h=-16t+64t+3$

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

$0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a} \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16} = \frac{64\±\sqrt{4096+192}}{32}$

$= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}$

So the ball will return to the ground at the positive value of $\boxed{\frac{8+\sqrt{67}}{4}}$ seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

$\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2$

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3 years ago

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Answer:

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Hope this helps have a wonderful day

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