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natulia [17]
3 years ago
6

Convert 1100112 into decimal number system.

Mathematics
2 answers:
alexira [117]3 years ago
6 0

What is 1100112 ternary in decimal? 1100112 from ternary to decimal is 986. Here we show you how to write 11001123 in decimal and how to convert 1100112 from base-3 to base-10.

Number:

11001123 in decimal

986

^10

Ostrovityanka [42]3 years ago
5 0

Answer:

986.10

Step-by-step explanation:

To convert ternary number 1100112 to decimal, follow these two steps:

Start from one's place in 1100112 : multiply ones place with 3^0, tens place with 3^1, hundreds place with 3^2 and so on from right to left

Add all the product we got from step 1 to get the decimal equivalent of 1100112.

Using the above steps, here is the work involved in the solution for converting 1100112 to decimal number (Don't forget that we start from ones place to so on...)

Decimal equivalent of "2" = 2 × 3^0 = 2

Decimal equivalent of "1" = 1 × 3^1 = 3

Decimal equivalent of "1" = 1 × 3^2 = 9

Decimal equivalent of "0" = 0 × 3^3 = 0

Decimal equivalent of "0" = 0 × 3^4 = 0

Decimal equivalent of "1" = 1 × 3^5 = 243

Decimal equivalent of "1" = 1 × 3^6 = 729

Decimal equivalent of "1100112" = 72924300932

1100112 = 986.10

Here is the final answer, The ternary number 1100112 converted to decimal is therefore equal to:

986.10

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Two adjacent angles form a complementary relationship. One angle is twelve more than twice the other angle. Draw a picture to re
Anon25 [30]

Answer:

The angles are 26 and 64

Step-by-step explanation:

When two angles are complementary, what this means is that the add up to 90 degrees

Now, let’s say one of the angles is x, the other angle is 12 more than twice it; mathematically that would be 2x + 12

Since they add up to be 90, we have

x + 2x + 12 = 90

3x + 12 = 90

3x = 90-12

3x = 78

x = 78/3

x = 26

The other angle is 2x + 12 = 2(26) + 12 = 52 + 12 = 64

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3 years ago
Factor −1/9 out of −1/9x−3.
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Answer:

-1/9 (x+27)

Step-by-step explanation:

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Solving for <em>Edges</em>

\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2

You would use this law under <em>two</em> conditions:

  • One angle and two edges defined, while trying to solve for the <em>third edge</em>
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_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:

  • Two angles and one edge defined, while trying to solve for the <em>second edge</em>
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* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

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