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marta [7]
4 years ago
6

192 students in 4 buses (finding unit rates)

Mathematics
1 answer:
kolezko [41]4 years ago
5 0
Divide 192 by 4 whichs comes out to be 48
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36% of the tarts that a baker baked were strawberry tarts. He baked 98 more chocolate tarts than strawberry tarts. How many tart
poizon [28]

Answer:

350

Step-by-step explanation:

100% - 36% = 64% (we first find out the remaining percentage)

Now we know there are 98 more chocolate tarts than strawberry tarts. We have to find out that percentage.

So, 64% - 36% = 28%

So 98 of the chocolate tarts make up 28%

x   --------> 100%

98 --------> 28%

Just follow the percentage formula.

98 * 100 = 9800

9800/28 = 350

3 0
3 years ago
Can you please fill in this table?
ELEN [110]

Answer:

Middle School In Favor: 25%

Middle School Not in Favor: 75%

High School In Favor 20%

High School Not In Favor 80%

Step-by-step explanation:

For the middle school in favor, we need to find the percent, which is 50 out of 200, so its 1/4, 25%

So the rest of the middle school is not in favor, which is 75%

High school is 60 not in favor, so we need to find the percentage. So 60 out is 300 is 20%

And we just subtract 20 from 100 which leaves us with 80

3 0
2 years ago
Read 2 more answers
What is the value of x in the equation 3x – 4y = 65, when y = 4?
vovangra [49]
<span>3x – 4y = 65
</span><span>3x – 4(4) = 65
3x - 16 = 65
3x = 81
x = 27</span>
6 0
3 years ago
Read 2 more answers
In Fig. 6.28, find the value of x and y and then show that AB || CD.​
poizon [28]

Answer:

Maybe 180° -50° = 130°

So I think x= 130°

Step-by-step explanation:

My opinion though

6 0
3 years ago
A school was attempting to determine the proportion of students who have access to the internet in their homes. Demographic data
Likurg_2 [28]

Answer:

Z = -1.789

P value = 0.036807

Step-by-step explanation:

Here

H0: p = 0.85 students will have access to the internet at home

Ha: p < 0.85 students will have access to the internet at home

As per the given data, out of 120 sampled students, 95 have access to internet at home

This is 79.17 % of the total number of sampled students.

The Z values is given by

Z = \frac{p-p'}{\sqrt{\frac{p(1-p)}{n} } }

Substituting the given values, we get -

Z = \frac{0.7917-0.85}{\sqrt{\frac{0.85(1-0.85)}{120} } }\\Z = -1.789

The sample proportion of 0.7917 is about -1.789 standard errors below the population proportion given in the null hypothesis.

Considering, result is significant at p < .05, the P-Value is .036807.

3 0
3 years ago
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