Question

What were the dimensions of the original photo?

Answer 1

Answer:

11 inches by 11 inches

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

Please have a look at the attached photo.  

My answer:

Given the information:

• The area of the reduced photo is 64 square inches
• The equation $(x-3)^{2}$= 64 where x is the  the side measure of the  original photo.

Let us solve for x by taking positive square root of both sides.\

$\sqrt{(x-3)^2}=\sqrt{64}\\\sqrt{(x-3)^2}=\sqrt{8^2}\\x-3=8$

<=> x = 11

So the dimensions of the original photo is 11  inches by 11 inches

We choose A

Hope it will find you well.