I believe the answer is true! Hope this helps!
We have to select all of the transformations that could change the location of the asymptotes of a cosecant of secant function.
So given function can be written as:
y=csc( sec(x))
First we need to determine the location of asymptote which is basically a line that seems to be touching the graph of function at infinity.
From attached graph we see that Asymptotes (Green lines) are vertical.
So Vertical shift or vertical stretch will not affect the location of asymptote because moving up or down the vertical line will not change the position of any vertical line.
only Left or right side movement will change the position of vertical asymptote. Which is possible in Phase shift and period change.
Hence Phase shift and Period change are the correct choices.
Answer: 1
Step-by-step explanation:
but why is it fx then the rest r g?
Question:
The cost of 12 kg sugar is $240 what will be the cost of 3 kg sugar.
Given:
- Cost of 12 kg sugar = $240
To find?
Answer :
<u>To find </u><u>c</u><u>o</u><u>s</u><u>t</u><u> </u><u>of</u><u> </u><u>3kg sugar first we have to find cost of 1 kg sugar</u><u>.</u>
- Cost of 1 kg sugar = Cost of total no. of sugar ÷Total sugar
- Cost of 1 kg sugar = $240/12
- Cost of 1 kg sugar = $20
<u>Now Let's find cost of 3 kg sugar</u>
Cost of 3kg sugar = total no of sugar ×Cost of 1 kg sugar
Cost of 3kg sugar = 3×$20
Cost of 3kg sugar = $60
Answer:
5 marbles are black.
Step-by-step explanation:
7-2=5