Question

What is the third term in sequence a(n)=3/2(-2)n-1

Answer 1

Answer:

-10

Step-by-step explanation:

First, you know n=3, so you plug that in. Then that equals A(n) = 3/2(-2)3-1, which can be simplified into 3/2*-6-1, then -9-1, and finally -10. [I did the 3/2*-6 by first: multiply -6*3=-18, then -18/2=-9.]

Hope this helps!

Answer 2

We have the general term of a sequence:

$a_n=\dfrac{3}{2}(-2)^{n-1}$

We must find the third term. Therefore substitute n = 3 to the equation:

$a_3=\dfrac{3}{2}(-2)^{3-1}=\dfrac{3}{2}(-2)^2=\dfrac{3}{2}(4)=3(2)=6$

Answer: The third term is equal 6.