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3 years ago

A 50-centimeter piece of wire in bent into a circle. What is the area of this circle?

1 answer:

7 0

When a wire is bent to form a circle then its length represents the circumference of the circle formed. Therefore in our case the circumference of the circle is 50 cm. we can use this to determine the radius of the circle and then determine the area. Circumference of a circle is given by \pi × diameter, (\pi = 3.142)
thus diameter will be given by 50 cm ÷ 3.142 = 15.9134 cm
the radius will be 15.9134 ÷2 = 7.9567 cm or ≈ 7.96 cm
The area of a circle is given by \pi × square of radius
Area = 3.142 × 7.96×7.96 = 199.0821 square cm
Thus the area of the circle formed is ≈ 199.08 square cm ( 2 decimal places)

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4)<br> Write an inequality for the graph below. If necessary, use<br> <= for < or >= for .

navik [9.2K]

9514 1404 393

Answer:

y < -1/4x -1

Step-by-step explanation:

The boundary line appears to go through the points (-4, 0) and (0, -1). This tells you it has a "rise" of -1 for a "run" of 4. The slope is ...

m = rise/run = -1/4

The y-intercept (b) is the point where the y-axis is crossed. The slope-intercept equation of the boundary line is ...

y = mx + b

y = -1/4x -1

The boundary line is dashed, so is not included in the solution set. The shading is below the line, so all y-values less than (but not equal to) the boundary line are in the solution set:

y < -1/4x -1

6 0

3 years ago

EXPERTs/ACE/GENIUS/TRUSTED HELPERs QUICK!!

Pavel [41]

X 0 y was 30

at x 12 y is about 55

12-0 = 12

55-30 = 25

25/12 = 2.08 inches per year average

so answer should be D

5 0

3 years ago

If the mean weight of 4 backfield members on the football team is 222 lb and the mean weight of the 7 other players is 198 lb, w

hoa [83]

To find the Mean or Average you have to add up all numbers it is asking for which in case are 222 and 198.

so you will add 222+198

That will equal 420

Then you will divide with the amount added together which is 2

420/2=210

so the mean of the 11 people is 210 or 210lbs

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3 years ago

Guys,whats 1 2/3 times 4?

Lemur [1.5K]

6 and 2/3 that is the answer

8 0

3 years ago

Read 2 more answers

Evaluate ,where e is the solid that lies between the cylinders x^2+y^2=1 and x^2+y^2=16, above the xy-plane, and below the plane

MA_775_DIABLO [31]

Assuming you're just computing the volume, i.e.

$\displaystyle\iiint_E\mathrm dV$

we should convert to cylindrical coordinates first, setting

$\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}$

so that the volume is given by

$\displaystyle\iiint_E\mathrm dx\,\mathrm dy\,\mathrm dz=\int_{\theta=0}^{\theta=2\pi}\int_{r=1}^{r=4}\int_{\zeta=0}^{\zeta=r\sin\theta+4}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta$

which has a value of $60\pi$ .

3 0

3 years ago