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finlep [7]
3 years ago
12

clothing store sells four shirts for $60.00. The next week, the store runs a special that is buy three shirts for $19.50 each, g

et the fourth free. Which is the better buy?​
Mathematics
2 answers:
Nimfa-mama [501]3 years ago
4 0

Answer:

its 19.50 get the fourth free

Step-by-step explanation:

qwelly [4]3 years ago
3 0

Answer:

the 19.50 for each one

Step-by-step explanation:

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How do i solve this?
storchak [24]
I hope it help you bye

6 0
3 years ago
Read 2 more answers
Fill in the missing blinks
Natalka [10]
3-4: Definition of supplementary angles
5: Simplify
4 0
3 years ago
A group of 50 people were asked their gender and if they liked cats. The data from the survey are shown in the Venn diagram. Det
Alja [10]

Answer:

a = 13,

b = 28,

c = 6,

d = 22,

e = 31

Step-by-step explanation:

E = 15 +16 = 31

6 males like cats ( the middle section) so C = 6

d = 6 +16 = 22

a = 19-6 = 13

b = 50-22 = 28

so in order: a = 13, b = 28, c = 6, d = 22, e = 31

7 0
3 years ago
Tonya and Pearl each completed a separate proof to show that alternate interior angles AKL and FLK are congruent. Who completed
zalisa [80]

Answer:

Tonya proof is correct
and Pearl proof is wrong

Step-by-step explanation:

AKL and GKB are obviously congruent. But the reasons given are different, One of the justification is Vertical Angles Theorem, and the other is Adjacent Angles.

But the correct justification is the Vertical Angles Theorem, because the angles are Vertically away from each other, or the angles are at opposite sides of each other. Which is when Vertical Angles Theorem is applied.
Making Tonya correct since that was the answer he given.

The definition of Adjacent Angles is incorrect, this Theorem is used when the angles are Adjacent to each other. When the angles are on the same line as the other angle, is when the definition of Adjacent Angles is applied. Not in this situation

8 0
1 year ago
A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard
bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44

In point a)  

\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}

  = \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2

value= (1- \frac{1}{k^2}) \times 100 \% =75\%

In point b)

\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma  \\\\= |(x-\mu)|\leq 2.5 \times 4.44  \\\\  = |(x-\mu)|\leq 1.11 \\\\ =  (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)

In point c)

\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\

In point d)

using standard normal variate

x=20.17\\\\  z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17

8 0
3 years ago
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