3 years ago

A person takes a trip, driving with a constant

1 answer:

8 0

For this problem, we are asked to calculate for the distance traveled. We set up the equations as follows:
Distance = 61 km/hr * (time + 20.8/60 s) Distance = 98.5 km/hr * time

We equate the two equations, then we can solve for the time spent on the trip. Hope this answers the question. Have a nice day.

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A 40.0-μFcapacitor is connected across a 60.0 Hz generator. An inductor is then connected in parallel with the capacitor. What i

amm1812

Answer:

The value of the inductance is 175.9 mH.

Explanation:

Given that,

Capacitor $C= 40.0\ \muF$

Frequency = 60.0 Hz

The inductor and capacitor is connected in parallel, the voltage across each of these elements is the same.

We have,

$V_{L}=V_{C}$

Using ohm's law

$I_{rms}\times X_{L}=I_{rms}\times X_{C}$

$X_{L}=X_{C}$

$2\pi f L=\dfrac{1}{2\pi f C}$

$L=\dfrac{1}{4\pi^2\times f^2\times C}$

Put the value into the formula

$L=\dfrac{1}{4\times\pi^2\times60.0^2\times40\times10^{-6}}$

$L=0.1759\ H$

$L=175.9\times10^{-3}\ H$

$L=175.9\ mH$

Hence, The value of the inductance is 175.9 mH.

5 0

4 years ago

A vehicle's mass is 1990kg. It is traveling at a speed of 28.0m/s. Determine the kinetic engine of the vehicle

irga5000 [103]

Answer: 780080

Explanation: BY FORMULA OF K.E

K.E= 1/2 MV^2

= 1/2 (1990)(28)^2

= 780080 JOULE

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3 years ago

Which type of galaxy has a central bar of stars instead of a rounded core?

Anastaziya [24]

Barred Spiral Galaxy

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3 years ago

This is the sum of all the forces applied to an object. It is usually separated into a horizontal and vertical component.

evablogger [386]

Answer: Net Force, also is referred to as Resultant Force

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3 years ago

Read 2 more answers

alpha decay is a nuclear decay in which a helium nucleus is emitted. If the helium nucleus has a mass of 6.8*10^-27 kg and is gi

almond37 [142]

Answer:

16520931.465 m/s

Explanation:

K = Kinetic energy = 5.8 MeV

m = Mass of nucleus = $6.8\times 10^{-27}\ kg$

Speed of a particle is given by

$v=\sqrt{\dfrac{2K}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 5.8\times 10^6\times 1.6\times 10^{-19}}{6.8\times 10^{-27}}}\\\Rightarrow v=16520931.465\ m/s$

The velocity is 16520931.465 m/s

4 0

3 years ago