1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
saw5 [17]
2 years ago
12

A less than youthful 82.6 kg physics professor decides to run the 26.2 mile (42.195 km) Los Angeles Marathon. During his months

of training, he realizes that one important component in running a successful marathon is carbo-loading, the consumption of a sufficient quantity of carbohydrates prior to the race that the body can store as glycogen to burn during the race. The typical energy requirement for runners is 1 kcal/km per kilogram of body weight, and each mole of oxygen intake allows for the release of 120 kcal of energy by oxidizing (burning) glycogen.
(a) If the professor finishes the marathon in 4:45:00 h, what is the professor's oxygen intake rate, in liters per minute, during the race if he metabolizes all of the carbo-loaded glycogen during the race and the ambient temperature is 21.5°C? 2.28 Read the problem statement again carefully. Is the air at standard temperature and pressure during the marathon? How would this affect the volume of 1 mol of oxygen? L/min
(b) The human body has an efficiency of 25.0%. Only 25.0% of the energy released from oxidizing glycogen is used as macroscopic mechanical energy, and the remaining 75.0% is used for body processes such as pumping blood and respiration, and then leaves the body through the skin via radiation, evaporative cooling, and other processes. What is the average mechanical power (in W) generated by the professor during the run? 197.561 What is the total energy required by the professor during the run? How efficient is the human body, and how long did the race last? W
(c) What is the change in entropy (in J/K) of the professor's body if his core temperature has risen to 38.3°C during the run and his skin temperature is at 36.0°C during the marathon? J/K
(d) What is the change of the entropy (in J/K) of the air surrounding the professor during the race if the ambient temperature remains constant at 21.5°C? J/K
Physics
1 answer:
o-na [289]2 years ago
4 0
Mem me e m even have. Jags. Shah. Shiv side esicjm is n meh dish so do indbbd
You might be interested in
The self inductance relates the magnetic flux linkage to the current through the coil. Calculate the self inductance L in units
Katen [24]

Answer:

Self inductance, L=127\ \mu H

Explanation:

It is given that,

Length of the coil, l = 5 cm = 0.05 m

Area of cross section of the coil, A=3\ cm^2=0.0003\ m^2

Number of turns in the coil, N = 130

The self inductance relates the magnetic flux linkage to the current through the coil and it is given by :

L=\dfrac{\mu_oN^2A}{l}

L=\dfrac{4\pi \times 10^{-7}\times (130)^2\times 0.0003}{0.05}

L = 0.000127 Henry

or

L=127\ \mu H

So, the self inductance of the coil is 127 microhenry. Hence, this is the required solution.

6 0
4 years ago
Steel is made of atoms of iron and carbon. Would iron
Nadusha1986 [10]

Still need the answer??

7 0
3 years ago
Read 2 more answers
How many miles will a car drive on 25 L of gasoline if the car average mileage is 60 km/gal. provide answer with correct signifi
Hunter-Best [27]

Answer:

Distance traveled by car in 25 L IS 396.15 km

Explanation:

We have given average millage of car = 60 km /gal

Means car travel 60 km in 1 gallon

The amount of gasoline = 25 L

We know that 1 L = 0.2641 gallon

So 25L=25\times 0.2641=6.6025gallon

As the car travels 60 km in 1 gallon

So traveled distance by car in 6.6025 gallon of gasoline = 60×6.6025 = 396.15 km

4 0
3 years ago
Physics quiz 11 th-12th grade helpp
FinnZ [79.3K]

5. The jogger's velocity is a constant 3.55 m/s between t = 4 s and t = 8 s.

6. Given a linear plot of velocity, the acceleration is determined by the slope of the line. Take any two points on the part of the plot after t = 8 s - for instance, we see it passes through (8 s, 3.5 m/s) and (10 s, 4 m/s) - and compute the slope:

(4 m/s - 3.5 m/s)/(10 s - 8 s) = (0.5 m/s)/(2 s) = 0.25 m/s^2

7. This amounts to finding the area between the velocity function and the time axis and between t = 4 s and t = 8 s. During this time, the velocity is 3.5 m/s. The time interval lasts 4 s. So the distance covered is

(3.5 m/s)*(4 s) = 14 m

8. After 4 seconds, Jimmy's speed decreases from 30.0 m/s to 27.2 m/s, so his acceleration (assuming it was constant) was

a = (27.2 m/s - 30.0 m/s)/(4 s) = -0.200 m/s^2

It's unclear what is meant by "rate of acceleration", since the acceleration is itself a rate. But maybe they just mean to ask for the acceleration, or possibly the magnitude?

4 0
4 years ago
Read 2 more answers
Plane a flies at a constant speed from new york to los angeles along a route which is 2000 miles. Plane b flies in the opposite
Lelechka [254]

Answer:

from los angeles distance plan a = 1111.08 mi

from los angeles distance plan b =  888.92 mi

Explanation:

given data

new york to los angeles distance = 2000 miles

Plane b speed = 100 mph faster than plane a

Plane b takes off  time = 1 hour after plane a

to find out

How far are they from los angeles when they pass

solution

we consider speed of plan a is = x mph

so speed of plan b will be = x + 100 mph

and we know plan b take here 1 hour less time than plan a so it mean time is distance divide speed i.e

\frac{2000}{x} - 1 =\frac{2000}{x+100}

solve it we get x = 400 mph

it mean here

plan a speed is 400 mph

and plan b speed is 500 mph

and

now we consider they meet at time = t hour  after a take off

then plan a travel  = 400 t

and plan b travel = 500 ( t - 1 )

add both distance that is equal to 2000 mi

so 400 t + 500 ( t -1 ) = 2000

400 t + 500 ( t -1 ) = 2000

400 t + 500 ( t-1) = 2000

solve we get

t = 2.777

so total distance travel plan a = 400 × 2.777 = 1111.08 mi

total distance travel plan b = 2000 - 1111.08

total distance travel plan b = 888.92 mi

4 0
3 years ago
Other questions:
  • Controlling the amount of current in a circuit by opposing the flow of charge
    7·2 answers
  • On a vehicle with a manual transmission, the point at which the engine begins to move the car as the clutch is released is calle
    8·1 answer
  • How can you use the position-time graphs for two in-line skaters to determine if and when one in-line skater will pass the other
    9·1 answer
  • X + 10 times X = 50 what is the answer
    11·1 answer
  • A ferry boat is 2.0 m wide and 4.0 m long. When a truck pulls onto it, the boat sinks 2.00 cm in the water. What is the weight o
    13·1 answer
  • What Do the edges of the rock look like?
    10·1 answer
  • Electric field is always perpendicular to the equipotential surface.<br><br> a. True<br> b. False
    9·1 answer
  • What’s the name of the muscle indicated on the image below?
    10·1 answer
  • When a force of 2.4 newtons is applied to a spring, the extension is 0.4 m. What is the spring constant?
    15·1 answer
  • Tendency of matter to change in shape, area, volume in response to a change in particular temperature is called
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!