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3 years ago

PLEASE HELP MEEEEEEEEEEEEEE

Mathematics

2 answers:

kogti [31]3 years ago

5 0

Answer:

D Line segments are the same and do not intersect

Step-by-step explanation:

They are parallell lines and are the same length

Fiesta28 [93]3 years ago

4 0

Answer:

eat my butt

Step-by-step explanation:

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Hi quick whats 18 x 1.25 step by step !!

Ivan

Answer:

22.5

Step-by-step explanation:

125

x 18

---------

1. first set up your problem

2 4

125

x 18

------

1000

2. next multiply the 8 by 5 getting 40, drop the 0 anf move the 4 to the top above 2.

3. multiply 8 by 2 getting 16, then add the 4 you have ontop of the 2 to the 16 getting 20. Drop the 0 and bring the 2 over and place it above the one.

4. multiply 8 by 1 getting 8 then add the 2 above the 1 to 8 getting 10. Then put the ten infront of the tw zeros. 1000

125

x 18

--------

1000

Next add a 0 as a place filler under the 0 at the end.

125

x 18

-------

1000

1250

Then multiply the 1 by 5, then 1 by 2, then finnaly 1 by 1, getting you 1250.

1000

+1250

add together

getting 2250

then move 2 decimal places over to get 22.5

3 0

3 years ago

Help with 21 would be much appreciated.

umka2103 [35]

Answer:

$\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}$

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

$\dfrac{AD}{CD}=\dfrac{CD}{DB}$

We have

$AD=14-8=6\\CD=y\\DB=8$

Substitute:

$\dfrac{6}{y}=\dfrac{y}{8}$ cross multiply

$y^2=(6)(8)$

$y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}$

For x use the Pythagorean theorem:

$x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}$

3 0

3 years ago

Due in 20 minutes!! please help

iris [78.8K]

Answer:

can

Step-by-step explanation: ;)

3 0

3 years ago

What are all the terms in the expression 4 m n + m + 5

Diano4ka-milaya [45]

4mn + m + 5

Terms: 4mn, m, 5

8 0

3 years ago

Which represents the solution(s) of the graphed system of equations, y = x2 – 2x and y = –2x – 1? (1, –1) (0, 0) and (0, –1) (0,

olganol [36]

ANSWER

No solution

EXPLANATION

The first equation is

$y = {x}^{2} - 2x$

and the second equation is

$y = - 2x - 1$

We equate the two equations to obtain;

${x}^{2} - 2x = - 2x - 1$

This implies that

${x}^{2} = - 2x + 2x - 1$

${x}^{2} = - 1$

There is no real number whose square is -1.

Therefore, the equation has no solution.

6 0

3 years ago

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