Options:
A) Cells require much less P to grow than N, so extra P will be used for ATP synthesis and result in a faster growth rate.
B) Cells will never consume all of the phosphate, because N is needed in higher quantities than P.
C) The final biomass of cells will be no different than if only 50% of the phosphate was provided.
D) The bacteria will import all of the ammonia to use for biosynthetic pathways.
Answer:A) Cells require much less P to grow than N, so extra P will be used for ATP synthesis and result in a faster growth rate.
Explanation: Chemoorganoheterophic Bacteria are bacteria which requires the supply of organic nutrients of Carbon and metabolic energy. If Ammonia and potassium are provided at equal amount or concentration, the least likely occurrence will be that
Cells require much less P(potassium) to grow than N(Nitrogen), so extra P(potassium) will be used for ATP synthesis and result in a faster growth rate. This is so because Chemoorganoheterophic Bacteria requires organic supply of nutrients in the form of Carbon and metabolic energy.
Reductions of chromosome numbered
A-<span>vaccine elicits a primary response, after which the subsequent infection is fought strongly and more rapidly.</span>
The correct answer for the question that is being presented above is this one: "c. Side A has a higher concentration of particles than side." The statement that correctly describes the diagram is that of <span>c. Side A has a higher concentration of particles than side</span>
