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rusak2 [61]
3 years ago
5

What is problem 25 please help!!

Mathematics
1 answer:
tino4ka555 [31]3 years ago
3 0
All you have to do is 
1) order data from lest to greatest 
2) find 2 middle number
3) add both numbers 
4) put fraction and then put 2 under the bottom 
(example)
                 27,33,38,41,42,52,60,64,68,72
                                 ^   ^                                  42+52=94 divide by 2= 94/2  
                              AVERAGE
Mean: 49.7        Median:47
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Answer:

98.90-1.984\frac{0.62}{\sqrt{103}}=96.98    

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The 95% confidence interval would be given by (96.98;100.82)    

Step-by-step explanation:

Information given

\bar X=98.90 represent the sample mean

\mu population mean (variable of interest)

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Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

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Since the Confidence is 0.95 or 95%, the significance is \alpha=0.05 and \alpha/2 =0.025, and the critical value for this case would be t_{\alpha/2}=1.984

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98.90-1.984\frac{0.62}{\sqrt{103}}=96.98    

98.90+ 1.984\frac{0.62}{\sqrt{103}}=100.82    

The 95% confidence interval would be given by (96.98;100.82)    

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