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insens350 [35]
3 years ago
8

How many solutions does the equation have? x^4 + 7x^2 – 144 = 0

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
7 0

Answer:

The equation has no real solutions. It has 2 imaginary, or complex solutions.

Step-by-step explanation:

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Help!
Lesechka [4]
Ok . since they are similar you can use similarity factor
4 0
3 years ago
Read 2 more answers
Which equation represents this statement?
Digiron [165]

Answer:

2n - 10 = 12

Step-by-step explanation:

the difference of twice a number and 10 is equal to 12

= twice a number minus 10 equal to 12

=> 2n - 10 = 12

4 0
3 years ago
Help please it’s for a test I’m so clueless!!!!!!
kumpel [21]

Answer:

h=12  A=144 sq. cm.

Step-by-step explanation:

pythagoream therom:

9^2+h^2=15^2

81+h^2=225

h^2=225-81

h^2=144

Sq. rt h^2=sq. rt 144

h=12cm

1/2(b1+b2)h

1/2(5+19)12

1/2(24)12

1/2(288)

a=144

6 0
3 years ago
I need help with this
Misha Larkins [42]

Answer:

(-3 , 0)

Step-by-step explanation:

The x-intercept is the point on which lies on the x-axis, so when the y is equal to 0.

They y-value can be seen as gaining 16 whole numbers every time the x gains 3.

1. Add intervals of +16 to the y-value (from -32) and intervals of +3 to the x-value (from -9) until the y-value equals 0.

Show:

(-9+3 , -32+16) = (-6 , -16)

(-6+3 , -16+16) = (-3 , 0)

The y-value in the end, is 0 with a x-value of -3.

5 0
3 years ago
A parallelogram with vertices (–4, 1), (1, 3), (2, 0), and (–3, –2) is translated left 3 units, up 5 units.
solmaris [256]
<u>|Vertices </u><em><u>ABCD</u></em><u>| (x - 3, y + 5)  |Vertices </u><em><u>A'B'C'D'|</u></em>
|        (-4, 1)       | (-4 - 3, 1 + 5)|         (-7, 6)         |
|         (1, 3)        | (1 - 3, 3 + 5) |         (-2, 8)         |
|         (2, 0)        | (2 - 3, 0 + 5) |         (-1, 5)         |
<u>|        (-3, -2)      |(-3 - 3, -2 + 5)|        (-6, 3)         |</u>

The vertices of (-4, 1), (1, 3), (2, 0), and (-3, -2) is (-7, 6), (-2, 8), (-1, 5), and (-6, 3).
The answer is D.
7 0
3 years ago
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