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Dennis_Churaev [7]
3 years ago
8

Bob can type 2 letters in 4 hours while Bill can do it in 6 hours. How many hours would it take them to type six letters togethe

r?
Mathematics
2 answers:
love history [14]3 years ago
7 0

Answer:

7.2 or 7 hours and 12 minutes

Step-by-step explanation:

together they type 1.2 letters in 1 hour so  they type 6 in 7.2 hours

jek_recluse [69]3 years ago
3 0

Answer:

Bill makes 1 in 3 hours and if he wanted to make 6 than it would take 18 hours and Bob makes 1 in 2 hours if he wanted to make 6 than it would take 12 hours

Step-by-step explanation:


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What is the rate of change of the water level , in feet per hour
miskamm [114]
A; rate of change is the same as slope, so, using the slope formula, m= \frac{y_{2} - y\1_{1}   }{ x_{2} - x_{1} }, where m is the slope and x_{1}, x_{2}, y_{1}, and y_{2} are the x and y values.

Plug in 2 points for x and y, water level being the y and time being the x since we're looking for the answer in ft/hr-- you can choose any two, but from the same row.

m= \frac{ 30-50}{4-0}
m= \frac{-20}{4}
m= \frac{-5}{1}
m= -5 ft/hr

4 0
3 years ago
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Ksju [112]

Answer:

D!

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A special deck of cards has 5 red cards, and 4 purple cards. The red cards are numbered 1, 2, 3, 4, and 5. The purple cards are
True [87]

Answer:

a. 9

b. 4/9 or 0.444

Step-by-step explanation:

R=red card={R1,R2,R3,R4,R5}

E=even card={R2,R4,P2,P4}

n(R)=5

n(E)=4

a.

There 5 red and 4 purple card so, the sample space would be

Sample space=S={R1,R2,R3,R4,R5,P1,P2,P3,P4}

number of elements in sample space=n(S)=9

So, the number of elements in the sample space are 9.

b.

P(E)=n(E)/n(S)

P(E)=4/9 or 0.444

Thus, the probability of an even numbered card is 0.444.

4 0
3 years ago
At a cell phone assembly plant, 77% of the cell phone keypads pass inspection. A random sample of 111 keypads is analyzed. Find
Serggg [28]

Answer:

The probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

Let <em>p</em> = the proportion of keypads that pass inspection at a cell phone assembly plant.

The probability that a randomly selected cell phone keypad passes the inspection is, <em>p</em> = 0.77.

A random sample of <em>n</em> = 111 keypads is analyzed.

Then the sampling distribution of \hat p is:

\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})\\\Rightarrow \hat p\sim N (0.77, 0.04)

Compute the probability that the proportion of passed keypads is between 0.72 and 0.80 as follows:

P(0.72

                             =P(-1.25

Thus, the probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.

8 0
4 years ago
Andy sold 125 baseball cards on the third day at his sporting goods store. On
castortr0y [4]
Can u give me thanks I need it so I can get 50 points plz
5 0
3 years ago
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