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Lera25 [3.4K]
3 years ago
9

Easy question just get mixed up please help.

Physics
1 answer:
Anna007 [38]3 years ago
7 0

Answer: 14 m/s

Explanation:

Assuming the velocity at the diving board is negligible,  the potential energy at the diving board height will convert to kinetic energy.

½mv² = mgh

v = √(2gh)

v =√2(9.8)(10))

v = 14 m/s

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A air glider of mass 1.0 kg that is equipped with a spring bumper travels at a speed of 2.5 m/s toward a second stationary glide
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Answer:

the final speed of the 0.75 kg cart is 2.86 m/s

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Given;

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mass of the stationary cart, m₂ = 0.75 kg

initial speed of the stationary cart, u₂ = 0

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Also, let the final speed of the air glider = v₁

Since the air glider has a spring bumper, the collision will be elastic.

Apply the following principle of conservation of linear momentum for elastic collision.

m₁u₁  +  m₂u₂  = m₁v₁   +   m₂v₂

(1 x 2.5)  + 0.75(0)  =  v₁   +  0.75v₂

2.5 = v₁  +  0.75v₂

v₁ = 2.5 - 0.75v₂ ----------- (1)

Apply one-dimensional velocity concept since the collision occured in one direction;

u₁ + v₁  = u₂  +  v₂

2.5  +  v₁   = 0   +  v₂

v₁ = v₂  - 2.5 ----- (2)

solve (1) and (2) together;

v₂  - 2.5 = 2.5 - 0.75v₂

v₂ + 0.75v₂ = 2.5  +  2.5

1.75v₂ = 5

v₂ = 5 / 1.75

v₂ = 2.86 m/s

Therefore, the final speed of the 0.75 kg cart is 2.86 m/s

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How many apples do you need to put in a bucket before it breaks
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