Answer:
Explanation:
We are not told where A and B are, but I'll assume that they are two points on the orbit of earth about the sun.
As that orbit is an ellipse, the two points likely do not have the same distance between the earth and sun.
As gravity varies with the inverse of the square of the distance (F = GMm/d²), the force at the closer distance will be greater than the force at the longer distance.
Answer:
139 N
Explanation:
Thats the answer on e2020
Answer:
We should only agree with the first statement of the first student but not with the second part of his statement. While as the statement of the other student is completely wrong.
Explanation:
The earth and the moon are locked in a process known as tidal locking. Tidal locking occurs when any object which revolves around other object takes the same amount of time to rotate around it's own axis as it takes to revolve around the planet.
This is exactly the case with moon and the earth system ,the moon is tidally locked with earth thus we cannot see the other side of the moon but this side is not dark as claimed by the first student but this side of the moon is also illuminated by the sunlight as the face of moon that we are able to see.
The second student is wrong as we cannot see the other side of moon from earth.
Answer:
The vapor pressure for a mist is 
Explanation:
From the question we are given that
The radius is 
The temperature is 
The vapor pressure of water 
The density of water is 
The surface tension of water is 
Generally the equation of that is mathematically represented as
Where P is the vapor pressure for mist
R is the ideal gas constant = 8.31
making P the subject in the formula
Answer:
u/2 √(1 + 3 cos² θ)
Explanation:
The object is thrown at an angle θ, so the velocity has two components, vertical and horizontal.
Initially, the vertical component is u sin θ and the horizontal component is u cos θ.
At the maximum height, the vertical component is 0 and the horizontal component is u cos θ.
The mean vertical velocity is:
(u sin θ + 0) / 2 = u/2 sin θ
The mean horizontal velocity is:
(u cos θ + u cos θ) / 2 = u cos θ
The net mean velocity can be found with Pythagorean theorem:
v² = (u/2 sin θ)² + (u cos θ)²
v² = u²/4 sin² θ + u² cos² θ
v² = u²/4 (1 − cos² θ) + u² cos² θ
v² = u²/4 (1 − cos² θ) + u²/4 (4 cos² θ)
v² = u²/4 (1 − cos² θ + 4 cos² θ)
v² = u²/4 (1 + 3 cos² θ)
v = u/2 √(1 + 3 cos² θ)
