(a) Compare your quadratic for h to the general quadratic ax² +bx +c. Perhaps you can see that ...
a = -16
b = 128
You use these numbers in the given formula to find the time when the ball is highest.
t = -b/(2a) = -128/(2(-16)) = 4 . . . . . . the time at which the ball is highest
(b) Evaluate the quadratic to find the height at t=4.
h = -16(4)² +128(4) +21
h = -256 +512 +21
h = 277
The maximum height of the ball is 277 ft.
It is not a right triangle
Last one
<span>f(x) = 4x and g(x) = 3x
</span><span> (fog)(x)
</span>you need take value of g(x), 3x, and put 3x instead of x in f(x) function
(fog)(x)=4*(3x)=12x
Answer:
Step-by-step explanation:
yes
Answer:
- laura's distance = max's distance + 2 3/4 feet
- max's distance = 5 feet 5 inches
Step-by-step explanation:
If you consider the English-language meaning of the description of the distances, you can see there might be several ways you could write an equation that says the same thing. Some of them are ...
laura's distance = max's distance + 2 3/4 feet
laura's distance - max's distance = 2 3/4 feet
laura's distance - 2 3/4 feet = max's distance
The first of these equations is shown as an answer above. The last of these equations gives max's distance directly, so is the most useful for finding that value.
laura's distance - 2 3/4 feet = max's distance
8 1/6 feet - 2 3/4 feet = max's distance
5 5/12 feet = max's distance . . . . . . do the arithmetic
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Describing addition and subtraction of mixed numbers is beyond the scope of this answer. Many calculators can work with fractions directly, in case you cannot do it by hand.
