Which phrases can be used to represent the inequality 12 minus 3 x greater-than-or-equal-to 9? Select two options.

Mathematics

2 answers:

koban [17]3 years ago

6 0

Answer: The correct answers are 3 and 5

Step-by-step explanation: Twelve less three times a number is at least nine.

Twelve minus the product of three and a number is no smaller than nine.

plz mark me!! thx!

Vika [28.1K]3 years ago

4 0

The answers would be options one and five

You might be interested in

For a fundraiser, a KIPP New Jersey is selling raffle tickets for $2 each

Finger [1]

Yes! If the raffle tickets are $2 and Amari supposedly purchased 8, that would make the total money for raffle tickets $16. Then if you take the 4 snacks for $1.50 each that would be $6.
16+6=22

7 0

3 years ago

Only answer if you’re sure :) thank you

adelina 88 [10]

Your answer is 1/2
Hope this helps!

3 0

3 years ago

Read 2 more answers

Slope-10 pass through (2,-5)

ahrayia [7]

Slope = -10
<span>pass through (2,-5)
y = mx + b
so
b = y - mx
b = -6 - (-10) (2)
b = -6 + 20
b = 14

equation
y = -10x + 14</span>

7 0

4 years ago

2,894 times 3 show your work

Svetradugi [14.3K]

8682 would be your answer.

8 0

3 years ago

How to integrate with steps:<br><br> (4x2-6)/(x+5)(x-2)(3x-1)

joja [24]

$\displaystyle\int\frac{4x^2-6}{(x+5)(x-2)(3x-1)}\,\mathrm dx$

You have a rational expression whose numerator's degree is smaller than the denominator's. This tells you you should consider a partial fraction decomposition. We want to rewrite the integrand in the form

$\dfrac{4x^2-6}{(x+5)(x-2)(3x-1)}=\dfrac a{x+5}+\dfrac b{x-2}+\dfrac c{3x-1}$

$\implies4x^2-6=a(x-2)(3x-1)+b(x+5)(3x-1)+c(x+5)(x-2)$

You can use the "cover-up" method here to easily solve for $a,b,c$ . It involves fixing a value of $x$ to make 2 of the 3 terms on the right side disappear and leaving a simple algebraic equation to solve for the remaining one.