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Annette [7]
2 years ago
11

Brian decided it was best to do what after the first snowfall had arrived?​

SAT
2 answers:
Harman [31]2 years ago
8 0
What is this question referring to
Komok [63]2 years ago
7 0

Answer:nothing

Explanation:

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Among all pairs of numbers whose difference is 14 find a pair whose product is as small as possible
zvonat [6]

The pair two numbers whose difference is 14 and the product is as small as possible (i.e. -49) are (-7,7)

<h3>What are word problems?</h3>

In mathematical concepts, word problems involve a crucial understanding of the problem and knowing which mathematical method and arithmetic operations are best suited to solving the problem.

If we assume that the smaller number should be = a and the larger number = a + 14.

Thus, their product (X) can be expressed as:

= a(a+14)

= a² + 14a

The smallest possible value implies the minimum value, i.e.

\mathbf{\dfrac{dX}{da} = 2a + 14}

Thus,

2a + 14 = 0

a = - 14/2

a = -7

Therefore, we can conclude that the pair of two numbers whose difference is 14 and the product is as small as possible (i.e. -49) is (-7,7).

Learn more about word problems here:

brainly.com/question/21405634

7 0
1 year ago
Tobias has a job walting tables where he earns a certain amount every month and an additional amount per table, according to the
anyanavicka [17]
Tobias is getting the job because of the graph
4 0
3 years ago
Which statement explains why br2 is a liquid at stp and i2.
Damm [24]

Answer:

(2) Molecules of I2 are polar, and molecules of Br2 are nonpolar.

(3) Molecules of Br2 have stronger intermolecular forces than molecules of I2.

(4) Molecules of I2 have stronger intermolecular forces than molecules of Br2.

None

Explanation:

5 0
2 years ago
(Only answer if u or someone related to u studies/studied in University of California).At what SAT score one can get into UCs an
Ivenika [448]

Answer:

The typical SAT scores for UC Davis are, for Reading and Writing:560-660; Math:570-700. UC Irvine R&W:580-650 Math:590-700. UCLA R&W:620-710 Math:600-740. UC San Diego R&W:600-680 Math:610-730

Explanation:

5 0
3 years ago
Suppose that 3. 33 g of acetone at 25. 0 °c condenses on the surface of a 44. 0-g block of aluminum that is initially at 25 °c.
Vlada [557]

The final temperature on the block is 25 degrees.

Heat is a form of energy. This question shows that energy is transferred from the acetone to the metal block.

Data given;

  • M1 = 3.33g
  • T1 = 25 degrees
  • M2 = 44g
  • T2 = 25 degree
  • C1 = 124.5 J mol K
  • C2 = 0.89 J/g K
<h3>Heat Transfer</h3>

Applying the principles of heat transfer,

Heat loss = Heat gain

m1c1(T1 - T3) = m2c2(T3 - T2)\\3.33*124.5*(25.0 - T3) = 44*0.89*(T3 - 25)\\10364.625 - 414.585T3 = 39.16T3 - 979\\10364.625+979 = 414.585T3 +39.16T3\\11343.25 = 453.745T3\\T3 = \frac{11343.25}{453.745} \\T3 = 24.999\\T3 = 25

From the calculation above, the final temperature on the block is 25 degrees.

Learn more on heat transfer here;

brainly.com/question/15003174

3 0
2 years ago
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