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3 years ago

Math: Slope help please

Mathematics

2 answers:

pishuonlain [190]3 years ago

3 0

Slope = (2+5)/(-3-1) = 7/-4 = -7/4

answer is B -7/4

swat323 years ago

3 0

(y2-y1) divided by (x2-x1)
In your case:
(2-5) divided by (-3-1)
Answer: -3/4

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"If you have a square and you cut off one corner, how many corners do you have

Stels [109]

Answer:

Step-by-step explanation:

it it cuts near the corner,then 5.

if it cuts along diagonal then 3

6 0

3 years ago

Read 2 more answers

HELP PLEASE 30 POINTS!!

Naya [18.7K]

Answer:

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Step-by-step explanation:

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4 0

3 years ago

Select the correct answer. Consider these three numbers written in scientific notation: 6. 5 × 103, 5. 5 × 105, and 1. 1 × 103.

Karo-lina-s [1.5K]

Scientific notation uses expression which gives easy access of order. The greatest number is $5.5 \times 10^5$ .It is greater by smallest number by 500 times.

<h3>How to convert a number to scientific notation?</h3>

It is usually of the form $a.bc.. \times 10^k$ exponent of 10 starts)

(we have 1 ≤ |a| < 10 ) (where |a| is magnitude of a without sign)

This notation is used to get some idea of how large or small a number is in terms of power of 10.

<h3>What are some basic properties of exponentiation?</h3>

If we have $a^b$ base and 'b' is called power or exponent and we call it "a is raised to the power b" (this statement might change from text to text slightly).

Exponentiation(the process of raising some number to some power) have some basic rules as:

$a^{-b} = \dfrac{1}{a^b}\\\\a^0 = 1 (a \neq 0)\\\\a^1 = a\\\\(a^b)^c = a^{b \times c}\\ a^b \times a^c = a^{b+c}$

The given numbers are:

First number = $6.5 \times 10^3 = 6500$
Second number = $5.5 \times 10^5 = 550000$
Third number = $1.1 \times 10^3 = 1100$

The smallest number is 1,100 and greatest is 550,000

Getting the division to get to know how many times the greatest number is larger than the smallest number, we get:

$\dfrac{5.5 \times 10^5}{1.1 \times 10^3} = \dfrac{5.5 \times 10^{5-3}}{1.1} = \dfrac{5.5}{1.1} \times 10^2 = 5 \times 10^2 = 500$

Thus, it is found that greatest number is $5.5 \times 10^5$ . It is greater by smallest number by 500 times.

Learn more about scientific notation here:
brainly.com/question/3112062

6 0

3 years ago

Please solve this please

ale4655 [162]

Answer:

C) $\frac{2z+15}{6x-12y}$

E) $\frac{7d+5}{15d^2+14d+3}$

F) $\frac{-7a-b}{6b-4a}$

Step-by-step explanation:

One is given the following equation

$\frac{z+1}{x-2y}-\frac{2z-3}{2x-4y}+\frac{z}{3x-6y}$

In order to simplify fractions, one must convert the fractions to a common denominator. The common denominator is the least common multiple between the given denominators. Please note that the denominator is the number under the fraction bar of a fraction. In this case, the least common multiple of the denominators is ( $6x-12y$ ). Multiply the numerator and denominator of each fraction by the respective value in order to convert the fraction's denominator to the least common multiple,

$\frac{z+1}{x-2y}-\frac{2z-3}{2x-4y}+\frac{z}{3x-6y}$

$\frac{z+1}{x-2y}*\frac{6}{6}-\frac{2z-3}{2x-4y}*\frac{3}{3}+\frac{z}{3x-6y}*\frac{2}{2}$

Simplify,

$\frac{z+1}{x-2y}*\frac{6}{6}-\frac{2z-3}{2x-4y}*\frac{3}{3}+\frac{z}{3x-6y}*\frac{2}{2}$

$\frac{6z+6}{6x-12y}-\frac{6z-9}{6x-12y}+\frac{2z}{6x-12y}$

$\frac{(6z+6)-(6z-9)+(2z)}{6x-12y}$

$\frac{6z+6-6z+9+2z}{6x-12y}$

$\frac{2z+15}{6x-12y}$

In this case, one is given the problem that is as follows:

$\frac{2}{3d+1}-\frac{1}{5d+3}$

Use a similar strategy to solve this problem as used in part (c). Please note that in this case, the least common multiple of the two denominators is the product of the two denominators. In other words, the following value: ( $(3d+1)(5d+3)$ )

$\frac{2}{3d+1}-\frac{1}{5d+3}$

$\frac{2}{3d+1}*\frac{5d+3}{5d+3}-\frac{1}{5d+3}*\frac{3d+1}{3d+1}$

Simplify,

$\frac{2}{3d+1}*\frac{5d+3}{5d+3}-\frac{1}{5d+3}*\frac{3d+1}{3d+1}$

$\frac{2(5d+3)}{(3d+1)(5d+3)}-\frac{1(3d+1)}{(5d+3)(3d+1)}$

$\frac{10d+6}{(3d+1)(5d+3)}-\frac{3d+1}{(5d+3)(3d+1)}$

$\frac{(10d+6)-(3d+1)}{(3d+1)(5d+3)}$

$\frac{10d+6-3d-1}{(3d+1)(5d+3)}$

$\frac{7d+5}{(3d+1)(5d+3)}$

$\frac{7d+5}{15d^2+14d+3}$

The final problem one is given is the following:

$\frac{3a}{2a-3b}-\frac{a+b}{6b-4a}$

For this problem, one can use the same strategy to solve it as used in parts (c) and (e). The least common multiple of the two denominators is ( $6b-4a$ ). Multiply the first fraction by a certain value to attain this denomaintor,