Six pairs of data yield r=0.444

April shoots an arrow upward into the air at a speed of 64 feet per second from a platform that is 11 feet high. The height of t

kogti [31]

Answer:

Maximum height of the arrow is 203 feets

Step-by-step explanation:

It is given that,

The height of the arrow as a function of time t is given by :

$h(t)=-16t^2+64t+11$ ..........(1)

t is in seconds

We need to find the maximum height of the arrow. For maximum height differentiating equation (1) wrt t as :

$\dfrac{dh(t)}{dt}=0$

$\dfrac{d(-16t^2+64t+11)}{dt}=0$

$-32t+64=0$

t = 2 seconds

Put the value of t in equation (1) as :

$h(t)=-16(2)^2+64(2)+11$

h(t) = 203 feet

So, the maximum height reached by the arrow is 203 feet. Hence, this is the required solution.

8 0

3 years ago

Masja [62]

Answer:

60 units

Step-by-step explanation:

Ratio of the perimeter = ratio of sides

Sides are in the ratio:

6 : 24

1 : 4

Perimeter of the first triangle:

4+5+6 = 15

Perimeter of the second triangle:

4(15) = 60

6 0

3 years ago

If ∠ABC and ∠CBD are supplementary angles, then m∠ABC + m∠CBD = 180° represents the definition of Question 2 options: A) complem

Oksanka [162]

Answer:

I would think it is supplementary.

Step-by-step explanation:

If 2 angles equal 180 degrees, then they are supplementary.

6 0

3 years ago

Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1, show that their volumes are in

Nuetrik [128]

<h2> $\large\bold{\underline{\underline{Question:-}}}$ </h2>

Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1 show that their volumes are in the ratio 3 : 1.

<h2> $\large\bold{\underline{\underline{Solution:-}}}$ </h2>

⇒ Ratio of heights of two cones = 1 : 3

⇒ Ratio of radius of their bases = 3 : 1

⇒ We know that V = 1/3πr²h

⇒ Ratio of their volume = V1 : V2

$\underline{ \underline{ \sf{Let's \: find \: the \: ratio \: of \: their \: volumes:}}}$

${ \implies{ \sf {V _{1} : V_{2}}}}$

${ \implies{ \sf{ \frac{1}{3} \pi \: { r_{1}}^{2} h_{1} : \frac{1}{3} \pi \: { r_{2} }^{2} h_{2}}}}$

${ \implies{ \sf{ {r_{1}}^{2} h_{1} : { r_{2}}^{2} h_{2}}}}$

${ \implies{ \sf{ \frac{ { r_{1} }^{2} }{ { r_{2} }^{2} } : \frac{ h_{2} }{ h_{1} } }}} \\$

${ \implies{ \sf{ \frac{ {3}^{2} }{ {1}^{2} } : \frac{3}{1} }}} \\$

${ \implies{ \sf{ \frac{9}{1} : \frac{3}{1} }}} \\$

${ \implies{ \sf{3 : 1}}} \\$

${ \therefore{ \sf{ \green{Ratio \: of \: their \: volumes = 3 : 1}}}}$

4 0

3 years ago

Why who is bored lol top ten tallest buildings

solong [7]

Answer:

Burj Khalifa: in Dubai - United Arab Emirates the height is 2,722′ to the tip
Shanghai Tower: in Shanghai, China the height is 2,073´
Makkah Clock Tower: in Saudi Arabia the height is 1,972´
Entisar Tower: in Dubai - United Arab Emirates the height is 1,870′
Ping An Finance Centre: in Shenzhen, China the height is 1,966′ to the tip
Lotte Tower: in Seoul, South Korea the height is 1,821′
One World Trade Center: in New York City the height is 1,792′ to the tip
Tianjin Chow Tai Fook Binhai Center: in Tianjin, China the height is 1,739′
CTF Finance Centre: in Guangzhou, China the height is 1,739′
China Zun: in Beijing, China the height is 1,731′

Hope it helps answer the question:)

7 0

3 years ago