If you are asked to find the 85th percentile, you are being asked to find a data value associated with an area of 0.85 to its left.
Percentile is a measure used in statistics indicating the value below which a given percentage of observations in a group of observations fall. For example, the 30 th percentile is the value below which 20% of the observations may be found.
Answer:
2
Step-by-step explanation:
if you multiply 2 by 3=6
- 2×2=4
- 3×3=9
Question:
Use the expression to complete the statements.

________ is the power
.
(0.5) is the ________
A ______ is another way to write
Answer:
0.5 is the base
10 is the power
-- another way to write
Step-by-step explanation:
Given

Required
Fill ion the gaps
is pronounced as; 0.5 raise to the power of 10
From the above statement, we can deduce the following:
0.5 is the base
10 is the power
Lastly, another way to write 
Express 0.5 as a fraction

Simplify the fraction


Hence:

Answer:
Step-by-step explanation:
Solution by substitution method
3x-4y=8
and 18x-5y=10
Suppose,
3x-4y=8→(1)
and 18x-5y=10→(2)
Taking equation (1), we have
3x-4y=8
⇒3x=4y+8
⇒x=(
4y+8)/
3 →(3)
Putting x=
(4y+8
)/3 in equation (2), we get
18x-5y=10
18(
(4y+8)
/3) -5y=10
⇒24y+48-5y=10
⇒19y+48=10
⇒19y=10-48
⇒19y= -38
⇒y=-
38
/19
⇒y= -2→(4)
Now, Putting y=-2 in equation (3), we get
x=4y+8
x=
(4(-2)+8)
/3
⇒x=
(-8+8)/
3
⇒x=
0/
3
⇒x=0
∴x=0 and y= -2