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Tpy6a [65]
3 years ago
5

/Q: DHSMV definition/ i have to write 20 characters for whatever reason lol

Physics
1 answer:
cluponka [151]3 years ago
6 0

<span><span>Department of Highway Safety and Motor Vehicles          OR</span></span>

<span><span /><span><span>Division of Highway Safety and Motor Vehicles </span></span></span>

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Which of these habitats has a highly salinity
Llana [10]
The answer for APEX Learning is Ocean
7 0
3 years ago
Read 2 more answers
A hockey player hits a rubber puck from one side of the rink to the other. It has a mass of .170 kg, and is hit at an initial sp
Dimas [21]

By using third law of equation of motion, the final velocity V of the rubber puck is 8.5 m/s

Given that a hockey player hits a rubber puck from one side of the rink to the other. The parameters given are:

mass m =  0.170 kg

initial speed u = 6 m/s.

Distance covered s = 61 m

To calculate how fast the puck is moving when it hits the far wall means we are to calculate final speed V

To do this, let us first calculate the kinetic energy at which the ball move.

K.E = 1/2mU^{2}

K.E = 1/2 x 0.17 x 6^{2}

K.E = 3.06 J

The work done on the ball is equal to the kinetic energy. That is,

W = K.E

But work done = Force x distance

F x S = K.E

F x 61 = 3.06

F = 3.06/61

F = 0.05 N

From here, we can calculate the acceleration of the ball from Newton second law

F = ma

0.05 = 0.17a

a = 0.05/0.17

a = 0.3 m/s^{2}

To calculate the final velocity, let us use third equation of motion.

V^{2} = U^{2} + 2as

V^{2}  = 6^{2} + 2 x 0.3 x 61

V^{2} = 36 + 36

V^{2} = 72

V = \sqrt{72}

V = 8.485 m/s

Therefore, the puck is moving at the rate of 8.5 m/s (approximately) when it hits the far wall.

Learn more about dynamics here: brainly.com/question/402617

5 0
2 years ago
The center of mass of the system is the point at which the total mass of the system could be concentrated without changing the _
Sveta_85 [38]

  The centre of mass of the system is the point at which the total

  mass of system could be concentrated without changing the moment

  of the system.

Centre of Mass is the point at which the whole mass of the system

is assumed to be concentrated.

 The general formula for the COM is:

              xₙ =  Σmₐxₐ / Σmₐ         where,  a = 1,2,3.........n

  Here the term Σ mₐ xₐ is called the first moment of the system and the

  denominator expression is called total mass of the system.

    Therefore, from this theory we can say that the moment of the system

    remain unchanged while calculating the COM.

  Hence, The centre of mass of the system is the point at which the total

  mass of system could be concentrated without changing the moment

  of the system.

   learn more about centre of mass here:

             brainly.com/question/3454419

                #SPJ4

8 0
1 year ago
To navigate, a porpoise emits a sound wave that has a wavelength of 3.3 cm. The speed at which the wave travels in seawater is 1
dedylja [7]

Answer:

2.2\times 10^{-5} s

Explanation:

We are given that  

The wavelength of sound wave=\lambda=3.3 cm=3.3\times 10^{-2}m/s

1 cm/s=10^{-2}m/s

Speed of sound wave,v=1522 m/s

We have to find the period of the wave.

We know that

Frequency=\nu=\frac{v}{\lambda}

Using the formula

Frequency =\frac{1522}{3.3\times 10^{-2}}=4.6\times 10^{4} Hz

Time period=\frac{1}{4.6\times 10^4}=0.22\times 10^{-4}\times \frac{10}{10^1}=2.2\times 10^{-4-1}=2.2\times 10^{-5}s

Using identity:\frac{a^x}{a^y}=a^{x-y}

Hence, the time period of the wave=2.2\times 10^{-5} s

4 0
3 years ago
There is an increase in energy in all of the following EXCEPT *
mars1129 [50]

Answer:

Freezing

Explanation:

I am pretty sure that the energy particles slow down when they freeze, making it the only one in which energy does NOT increase. Hope I helped.

5 0
3 years ago
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