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Svetlanka [38]
3 years ago
7

An ant carries a morsel of food 4.26 meters along a straight path to his nest. He then turns around and follows the path back to

the source of the food. What is his displacement when he arrives back at the food source?
Physics
1 answer:
Basile [38]3 years ago
6 0
The displacement is zero. The most important concept to understand is the difference between displacement and total distance traveled. Total distance traveled would be tracking the length of the entire path the ant walked for the whole time (4.26m x 2). Displacement is how far from a designated origin (here, the food source) the ant ended up at the end of the time. Mathematically, the ant walked 4.26m from food source to nest (+4.26m) and then walked from the nest to food source (-4.26m), so the net displacement is [+4.26] + [-4.26] = 0m.
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stellarik [79]

Answer: 0.516 ft/s

Explanation:

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3 years ago
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mylen [45]

The distance covered by the acorn is 3.136 m.

<u>Explanation:</u>

The time taken for the acorn to hit the ground is 0.8 s. As it is a free fall, the acorn will be completely under the influence of gravity. So the acceleration will be acceleration due to gravity.

Then using the second law of equation,

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