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Dima020 [189]
2 years ago
14

"A block of metal weighs 40 N in air and 30 N in water. What is the buoyant force on the block due to the water? The density of

water is 1000 kg/m3."
Physics
2 answers:
Alja [10]2 years ago
6 0

Answer:

buoyant force on the block due to the water= 10 N

Explanation:

We know that

buoyant force(F_B) on a block= weight of the block in air (actual weight) - weight of block in water.

Given:

A block of metal weighs 40 N in air and 30 N in water.

F_B =  40-30= 10 N

therefore,  buoyant force on the block due to the water= 10 N

Yuliya22 [10]2 years ago
3 0

Answer:

10 N

Explanation:

We are given that

Weight of block of metal in air=40 N

Actual weight of object=Weight of object in air

Actual weight of block of metal=40 N

Apparent weight of block of metal=Weight of block in water

Weight of block in water=30 N

Apparent weight of block=30 N

Density of water=1000 kg /cubic meter

We have to find the buoyant force on the block due to water.

Buoyant force=Actual weight-apparent weight

Buoyant force on the block due to water=40-30=10 N

Hence, the buoyant force on the block due to the  water=10 N

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frez [133]

Answer:

Explanation:

a= 7.8i + 6.6j - 7.1k

b=   -2.9 i+ 7.4 j+ 3.9k , and

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r = a - b +c

=7.8i + 6.6j - 7.1k - ( -2.9i + 7.4j+ 3.9k )+ ( 7.6i + 8.8j + 2.2k)

= 7.8i + 6.6j - 7.1k +2.9i - 7.4j- 3.9k )+  7.6i + 8.8j + 2.2k

= 18.3 i +18.3 j - k

the angle between r and the positive z axis.

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the angle between r and the positive z axis.

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45 degree

6 0
3 years ago
An airplane traveling at one third the speed of sound (i.e., 114 m/s) emits a sound of frequency 3.72 kHz. At what frequency doe
nlexa [21]

Answer:

f'=5.58kHz

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f=3.72kHz\\v=342m/s\\v_o=0m/s\\v_s=-114m/s

f'=\frac{(342+0)}{(342-114)}3.72\times10^3\\f'=\frac{342}{228}3.72\times10^3\\f'=(1.5)3.72\times10^3\\f'=5580Hz=5.58kHz

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2 years ago
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Answer:

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Montano1993 [528]

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Kinetic energy depends on the mass and the speed of a moving object.

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