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Dima020 [189]
3 years ago
14

"A block of metal weighs 40 N in air and 30 N in water. What is the buoyant force on the block due to the water? The density of

water is 1000 kg/m3."
Physics
2 answers:
Alja [10]3 years ago
6 0

Answer:

buoyant force on the block due to the water= 10 N

Explanation:

We know that

buoyant force(F_B) on a block= weight of the block in air (actual weight) - weight of block in water.

Given:

A block of metal weighs 40 N in air and 30 N in water.

F_B =  40-30= 10 N

therefore,  buoyant force on the block due to the water= 10 N

Yuliya22 [10]3 years ago
3 0

Answer:

10 N

Explanation:

We are given that

Weight of block of metal in air=40 N

Actual weight of object=Weight of object in air

Actual weight of block of metal=40 N

Apparent weight of block of metal=Weight of block in water

Weight of block in water=30 N

Apparent weight of block=30 N

Density of water=1000 kg /cubic meter

We have to find the buoyant force on the block due to water.

Buoyant force=Actual weight-apparent weight

Buoyant force on the block due to water=40-30=10 N

Hence, the buoyant force on the block due to the  water=10 N

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The constructive interference is between two waves with the same phase, that is, each crest and trough correspond with the crest and trough of the another getting as result a wave with twice the amplitude of the original one.

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If light passes for a slit it will get a diffraction pattern in a screen, at which each bright pattern corresponds to a crest and a dark pattern to a trough, as a consequence of constructive interference and destructive interference in different points of its propagation to the screen.

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