The tangent of an angle is the ratio of the opposite side to the adjacent side.
... tan(45°) = (height above eye level)/(20 m)
... height above eye level = (20 m)·tan(45°) = (20 m)·1 = 20 m
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Eye level is 1.7 m above ground, so the height of the flagpole above ground is
... height of pole = height above eye level + height of eye level
... height of pole = 20 m + 1.7 m = 21.7 m
Answer: 139
Step-by-step explanation:
100% + 10% = 110%
110/100 x 126 = 138.6 ≈ 139
hope this helped, if it’s wrong I’m so so so sorry :(
The area of the triangle is
A = (xy)/2
Also,
sqrt(x^2 + y^2) = 19
We solve this for y.
x^2 + y^2 = 361
y^2 = 361 - x^2
y = sqrt(361 - x^2)
Now we substitute this expression for y in the area equation.
A = (1/2)(x)(sqrt(361 - x^2))
A = (1/2)(x)(361 - x^2)^(1/2)
We take the derivative of A with respect to x.
dA/dx = (1/2)[(x) * d/dx(361 - x^2)^(1/2) + (361 - x^2)^(1/2)]
dA/dx = (1/2)[(x) * (1/2)(361 - x^2)^(-1/2)(-2x) + (361 - x^2)^(1/2)]
dA/dx = (1/2)[(361 - x^2)^(-1/2)(-x^2) + (361 - x^2)^(1/2)]
dA/dx = (1/2)[(-x^2)/(361 - x^2)^(1/2) + (361 - x^2)/(361 - x^2)^(1/2)]
dA/dx = (1/2)[(-x^2 - x^2 + 361)/(361 - x^2)^(1/2)]
dA/dx = (-2x^2 + 361)/[2(361 - x^2)^(1/2)]
Now we set the derivative equal to zero.
(-2x^2 + 361)/[2(361 - x^2)^(1/2)] = 0
-2x^2 + 361 = 0
-2x^2 = -361
2x^2 = 361
x^2 = 361/2
x = 19/sqrt(2)
x^2 + y^2 = 361
(19/sqrt(2))^2 + y^2 = 361
361/2 + y^2 = 361
y^2 = 361/2
y = 19/sqrt(2)
We have maximum area at x = 19/sqrt(2) and y = 19/sqrt(2), or when x = y.
The answer is the fourth one. Trust me I had the same question
Answer:
44
Step-by-step explanation:
to find circumference of a circle you need to multiple r (7 in here) with 2 and pi
therefore the answer is : 2x7x3 = 42 or 44 approximately
