Answer:
<h2>616 Short with white flower
</h2><h2>1850 Tall with white flower
</h2><h2>1850 Short with purple flower</h2>
Explanation:
A dihybrid cross is in which two genes of two different traits are crossed
As given, two dihybrid pea plants (tall with purple flower) are mated, resulting 5550 out of 9866 were tall with purple.
T= tall
t= short,
P= purple,
p= white;
So genotype of parents are TtPp ; T is dominant over t, P is dominant over p.
Crossing between two parens= TtPp × TtPp
so gamets are = parent 1: TP, Tp, tP, tp and parent 2: TP, Tp, tP, tp
Hence the four different gametes formed.
Now arrange the gametes on the top and left side of a Punnett square it'll genotypically results into different combinations, by which phenotypic ratios can be calculated.
offspring are = TTPP, TTPp, TtPP, TtPp....................TTpp, Ttpp.....ttPP, ttPp.......ttpp
(T_P_)= Tall with purple flower,
(T_pp)= tall with white flower,
(ttP_)= short with purple flower,
(ttpp)= short with white flower.
so it show 12:3:3:1 ratio'
Phenotypic classes are:
616 Short with white flower
1850 Tall with white flower
1850 Short with purple flower
