Answer:
Four daughter cells are produced each with 40 chromosomes. The daughter cells would exhibit genetic variations and would not be genetically identical to each other.
Explanation:
Meiosis is a cell division that forms four daughter cells from one parent cell as two sequential division meiosis I and meiosis II do not include any DNA replication between them. Crossing over during prophase-I of meiosis-I includes the exchange of genetic segments and occurs between the homologous chromosomes. It produces new gene combinations in the daughter cells which were otherwise not present in the parent cell.
Since there is no DNA replication between meiosis I and meiosis II, the daughter cells have half the number of the chromosomes compared to the parent cell. This occurs as homologous chromosomes move towards the opposite pole during anaphase I.
Therefore, a parent cell with 80 chromosomes will make a total of 4 daughter cells by meiosis. Each daughter cell would have 40 chromosomes. These daughter cells would have some new gene combinations and would be genetically dissimilar among themselves.
Outer hair cells change their axial dimensions in response to electrical stimulation.
What is basilar membrane motion?
Hair cell stereocilia move as a result of the basilar membrane's movement. The tectorial membrane and the hair cells, which are connected to the basilar membrane, move along with it when it moves, and the stereocilia bend in response to the relative motion of the tectorial membrane.
The hair cells that are linked to the auditory nerve fibers are stimulated by the basilar membrane's movement. While the outside hair cells actively affect the basilar membrane's vibrations, the inner hair cells convert hydromechanical vibration into action potentials.
With each sound cycle, the intracellular voltage of the outer hair cells varies, causing them to lengthen and contract. This increases the organ of Corti's vibration, enabling exceptionally high hearing sensitivity and frequency selectivity.
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The answer is b) "No known sexual mode of spore formation
We'll make the alleles: Cc.
C is a healthy parent, and c is the cystic fibrosis (recessive).
If you make a punnett square and the parents are both Cc (healthy), then you would get CC, Cc, Cc, and cc. That cc is a 25% chance that the offspring will have that, which means there is a 25% chance the child will have cystic fibrosis.
Two healthy parents can have a child with cystic fibrosis if both the parents have the dominant allele and recessive allele, if both the parents have heterozygous alleles.
This person is a male. A female would have two X chromosomes.
