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Naddik [55]
3 years ago
8

HELP ILL GIVE BRAINLIEST

Mathematics
2 answers:
9966 [12]3 years ago
4 0

Answer:

linear increasing

Step-by-step explanation:

For the section labeled B, the line goes up as x increases.  This means the line is increasing

dolphi86 [110]3 years ago
4 0

Answer:

Linear increasing

Step-by-step explanation:

The slope of interval B is constant since it's a straight line, which makes it linear. The line in interval B is pointing upward so it's increasing.

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(-4f + 9) - (8f + 9) =<br> Math pls help
Salsk061 [2.6K]

Answer:

-12f

Step-by-step explanation:

4 0
3 years ago
In TriangleARC, m AngleA = 70°. What is the measure of arc AC?
rusak2 [61]
I found the image that should have accompanied this problem.

The triangle inside the circle is an isosceles triangle. It has 2 equal sides and 2 equal angles. 

Angle A = 70° , Angle C is also 70°. This leaves angle R having 40°.

The arc opposite angle R is twice the measure of its angle.

Angle R = 40°
Arc AC = 40° x 2 = 80°

The measure of arc AC is 80°.
4 0
3 years ago
write in complete standard form then give the center and radius of each circle and graph the equation x2+y2-4x-12y-9=0
kakasveta [241]
Standard form;

(x - 2)² + (y - 6)² = 49

the center-radius form of the circle equation is in this format;

(x - h)² + (x - k)² = r²

so the center of the circle is; (2, 6)
so the radius of the circle is; 7

hope that helps, God bless!
8 0
4 years ago
Select the correct answer.
andrew-mc [135]

Answer:

OPTION C

Step-by-step explanation:

We have the following rules:

$ \sqrt[a]{x} = x^{\frac{1}{a} $    and

$ x^a . x^b = x^{a + b} $

OPTION A: $ x \sqrt[7]{x} $

= $x . x^{\frac{1}{7} $

= $ x^{1 + \frac{1}{7} $

$ = x^{\frac{8}{7} $ $ \ne x^{\frac{9}{7} $

So, it can be eliminated.

OPTION B: $ \bigg ( \frac{1}{\sqrt[7]{x}} \bigg )^9 $

= $ \bigg ( \frac{1}{x^{\frac{1}{7}}} \bigg )^9 $

= $ \bigg ( x^ {\frac{-1}{7}} \bigg )^9 $

= $ x^{\frac{-9}{7}} $

So, this option is also eliminated.

OPTION C: $ x . \sqrt[7]{x} $

= $ x . x^{\frac{1}{7}} $

= $ x^{1 + \frac{1}{7}} $

= $ x^{\frac{9}{7}} $

So, OPTION C is the answer.

5 0
3 years ago
Consider the function f(x) = 20/√x and its second-degree polynomial P2 (x) = 20 - 10(x-1) + 7.5(x-1)^2 at x=0.8. Compute the val
krok68 [10]

Answer:

f (0.8) = 22.3607 and P_{2} (0.8) = 22.300.

Step-by-step explanation:

According to the statement, f (x) = \frac{20}{\sqrt{x}}  and  P_{2}(x) = 20 - 10 (x-1) + 7.5 (x-1) ^ 2. Based on these definitions, at x=0.8 produce:

f (0.8) = \frac{20}{\sqrt {0.8}} = 22.3607.  On the other hand, you have to:

P_{2} (0.8) = 20 - 10 (0.8 -1) +7.5 (0.8 -1)^2

P_{2} (0.8) = 20 - 10 (-0.2) +7.5 (-0.2)^2 = 22.300

Then, it can be affirmed that f (0.8) = 22.3607 and P_{2} (0.8) = 22.300.

3 0
4 years ago
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