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Simora [160]
3 years ago
6

Kinetic Theory: Tutorial

Chemistry
1 answer:
ozzi3 years ago
3 0

Answer:

The heavy particles move across the chamber because of the diffusion property of gas particles. The particles move in straight lines and change directions only when they collide with other molecules or the walls of the chamber.

Explanation:

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A solid ball has a density of 2.5 g/cm and a volume of 20 cm3. What is the
Svetach [21]

Answer:

50 g

Explanation:

d= m/v

rearranging the above equation

m = d x v

m = 2.5 g x 20 g/cm3

m = 50 g

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You need to prepare 100.0 mL of a pH=4.00 Get the buffer solution using 0.100 M benzoic acid (pKa = 4.20) and 0.140 M sodium ben
nikklg [1K]
Ok let me explain the procedure to you:
The buffer solution is like this:
pH = pKa + log [salt]/[acid] 4 = 4.20 + log [salt] / [acid] -0.20 = log [salt]/[acid]
If you <span>Solve for [salt]/[acid] This gives ratio of moles.
</span><span>Take amount of acid be x L and then amount of salt will be 0.1-x Now molarity*volume=number of moles
</span>I know that with this you will be able to get to the result. Hope this helps

8 0
3 years ago
Please help me
Dmitriy789 [7]

Answer:

divergent

Explanation:

I believe it is divergent.

7 0
3 years ago
The enthalpy of fusion for Hg is 2.29 kJ/mol. What is the energy change when 78.0 g of Hg melts at −38.8°C?
Veronika [31]

The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.

<h3>What is Enthalpy of Fusion ?</h3>

The amount of energy needed to change 1 mole of substance under state change at constant temperature and pressure is called enthalpy of fusion. It is also known as Latent heat of fusion. Unit of enthalpy of fusion is kJ/mol.

<h3>How to find the change in energy ? </h3>

To find the change in energy use this expression:

q = n ΔH

where

q = Energy change

n = number of moles

ΔH = Molar enthalpy

Number of moles (n) = \frac{\text{Given mass}}{\text{Molar mass}}

                                  = \frac{78.0\ g}{200\ \text{g/mol}}

                                  = 0.39 mol

Now put the values in above formula we get

q = n ΔH

  = 0.39 mol × 2.29 kJ/mol

  = 0.89 kJ

Thus from the above conclusion we can say that The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.

Learn more about the Latent heat of fusion here: brainly.com/question/87248

#SPJ1

8 0
2 years ago
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