Answer:
120
Step-by-step explanation:
A: D: 10 ≤ b ≤ 12
R: 0 ≤ W(b) ≤ 120
B: D: 0 ≤ b ≤ 10
R: 12 ≤ W(b) ≤ 120
C: D: 0 ≤ b ≤ 120
R: 0 ≤ W(b) ≤ 10
D: D: 0 ≤ b ≤ 10
R: 0 ≤ W(b) ≤ 120
The sum of all interior angles in a polygon is
180(n - 2), where n = the number of sides in the polygon.
now, notice this figure above, it has 5 sides, namely is a PENTAgon, so the sum of all its interior angles is 180( 5 - 2), or 540, therefore
Answer:
30 inches squared
Step-by-step explanation:
First, find the area of the entire frame using length times height. 9*6 is 54 inches squared. Then, find the area of the middle space the same way. 6*4 is 24 inches squared. Lastly, subtract the middle from the entire frame's area. 54-24 is 30 inches squared.
I hope you have heard about the congruency rules like SSS, SAS, ASA
Those are the least amount of information you need
Answer:
2a) -2
b) 8
Step-by-step explanation:
<u>Equation of a parabola in vertex form</u>
f(x) = a(x - h)² + k
where (h, k) is the vertex and the axis of symmetry is x = h
2 a)
Using the equation of a parabola in vertex form, a parabola with vertex (2, -6):
f(x) = a(x - 2)² - 6
If one of the x-axis intercepts is 6, then
f(6) = 0
⇒ a(6 - 2)² - 6 = 0
⇒ 16a - 6 = 0
⇒ 16a = 6
⇒ a = 6/16 = 3/8
So f(x) = 3/8(x - 2)² - 6
To find the other intercept, set f(x) = 0 and solve for x:
f(x) = 0
⇒ 3/8(x - 2)² - 6 = 0
⇒ 3/8(x - 2)² = 6
⇒ (x - 2)² = 16
⇒ x - 2 = ±4
⇒ x = 6, -2
Therefore, the other x-axis intercept is -2
b)
Using the equation of a parabola in vertex form, a parabola with vertex (2, -6):
f(x) = a(x - 2)² - 6
If one of the x-axis intercepts is -4, then
f(-4) = 0
⇒ a(-4 - 2)² - 6 = 0
⇒ 36a - 6 = 0
⇒ 36a = 6
⇒ a = 6/36 = 1/6
So f(x) = 1/6(x - 2)² - 6
To find the other intercept, set f(x) = 0 and solve for x:
f(x) = 0
⇒ 1/6(x - 2)² - 6 = 0
⇒ 1/6(x - 2)² = 6
⇒ (x - 2)² = 36
⇒ x - 2 = ±6
⇒ x = 8, -4
Therefore, the other x-axis intercept is 8
