Answer:
0.01 second ; 0.008 seconds; 800 seconds
Explanation:
Given that:
Sending rate = 1000 bps
Rate of 1000 bps means that data is sent at a rate of 1000 bits per second
Hence, to send out 10 bits
1000 bits = 1 second
10 bits = x
1000x = 10
x = 10 / 1000
x = 0.01 second
2.)
A single character 8 - bits
1000 bits = 1 second
8 bits = (8 / 1000) seconds
= 0.008 seconds
3.)
100,000 characters = (8 * 100,000) = 800,000
1000 bits = 1 second
800,000 bits = (800,000 / 1000)
= 800 seconds
Answer:
The code to this question can be given as:
Code:
int lastVector = newScores.size() -1; //define variable lastVector that holds updated size of newScores.
newScores = oldScores; //holds value.
for (i = 0; i < SCORES_SIZE - 1; i++) //define loop.
{
newScores.at(i) = newScores.at(i+1); //holds value in newScores.
}
newScores.at(lastVector) = oldScores.at(0); //moving first element in last.
Explanation:
- In the given C++ program there are two vector array is defined that are "oldScores and newScores". The oldScores array holds elements that are "10, 20, 30, 40".
- In the above code, we remove the array element at first position and add it to the last position. To this process, an integer variable "lastVector" is defined.
- This variable holds the size of the newScores variable and uses and assigns all vector array elements from oldScores to newScores. In the loop, we use the at function the removes element form first position and add in the last position.
- Then we use another for loop for print newScores array elements.
One of the things that are a challenge, is that you have to get the correct puntuation, correct capitilization, because it's a buisness email. You ont want to mess a buisness email up. You also have to have no repating phrases and sentences. You can't be adding random words and saying "and" all the time.
Answer:
jddjjddjdjdjjsjsjejejejjejejejjdjdjeje
I would say C. podcast??? not for sure
