Answer:
D. Workflow management systems
Explanation:
Workflow management systems can be defined as a strategic software application or program designed to avail companies the infrastructure to setup, define, create and manage the performance or execution of series of sequential tasks, as well as respond to workflow participants.
Some of the international bodies that establish standards used in workflow management are;
1. World Wide Web Consortium.
2. Workflow Management Coalition.
3. Organization for the Advancement of Structured Information Standards (OASIS).
Workflow management systems facilitates the automation and management of business processes and controls the movement of work through the business process.
<em>The following are various types of workflow management systems used around the world; YAWL, Windows Workflow Foundation, Apache ODE, Collective Knowledge, Workflow Gen, PRPC, Salesforce.com, jBPM, Bonita BPM etc.</em>
Answer: The one that gives you more vibe that its correct.
Explanation:
Physical activity could help reduce the chance ofheart disease
Answer:
Number of packets ≈ 5339
Explanation:
let
X = no of packets that is not erased.
P ( each packet getting erased ) = 0.8
P ( each packet not getting erased ) = 0.2
P ( X ≥ 1000 ) = 0.99
E(x) = n * 0.2
var ( x ) = n * 0.2 * 0.8
∴ Z = X - ( n * 0.2 ) / 
~ N ( 0.1 )
attached below is the remaining part of the solution
note : For the value of <em>n</em> take the positive number
Answer:
The program in Python is as follows:
num1 = int(input())
num2 = int(input())
if num1 >=0 and num2 >= 0:
print(num1+num2)
elif num1 <0 and num2 < 0:
print(num1*num2)
else:
if num1>=0:
print(num1**2)
else:
print(num2**2)
Explanation:
This gets input for both numbers
num1 = int(input())
num2 = int(input())
If both are positive, the sum is calculated and printed
<em>if num1 >=0 and num2 >= 0:</em>
<em> print(num1+num2)</em>
If both are negative, the products is calculated and printed
<em>elif num1 <0 and num2 < 0:</em>
<em> print(num1*num2)</em>
If only one of them is positive
else:
Calculate and print the square of num1 if positive
<em> if num1>=0:</em>
<em> print(num1**2)</em>
Calculate and print the square of num2 if positive
<em> else:</em>
<em> print(num2**2)</em>
