ahaha good one
Step-by-step explanation:
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Answer:
The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft
Step-by-step explanation:
Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²
For maximum volume, the side length, s of the cube must all be equal ;
Therefore area of one side = s²
Number of sides in a cube with top open = 5 sides
Area of surface = 5 × s² = 180
Therefore s² = 180/5 = 36
s² = 36
s = √36 = 6 ft
Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.
Answer:
211%
Step-by-step explanation:
To calculate the percentage change between these two numbers we need to divide the end result from the initial starting point. Once we do this we need to multiply the product by 100 to get the percentage value.
95 / 45 = 2.11111
2.11111 * 100 = 211.11%
Finally, we can see that the percentage change from 45 ft. to 95 ft. is 211.11%. If we round this to the nearest whole percent it would be a change of 211%
