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aleksandr82 [10.1K]
3 years ago
14

A rock of mass m = 0.0450 kg is attached to one end of a string and is whirled around in a horizontal circle. If the radius of t

he circle is 0.580 m and the angular speed is 2.34 rad/s. What is the tension in the string?
Physics
1 answer:
AleksAgata [21]3 years ago
8 0

Answer:

Tension, T = 0.1429 N

Explanation:

Given that,

Mass of the rock, m = 0.0450 kg

Radius of the circle, r = 0.580 m

Angular speed, \omega=2.34\ rad/s

The tension in the string is balanced by the centripetal force acting on it. It is given by :

T=\dfrac{mv^2}{r}

Since, v=r\omega

T=\dfrac{m(r\omega)^2}{r}

T=\dfrac{0.0450\times (0.580\times 2.34)^2}{0.580}

T = 0.1429 N

So, the tension in the string is 0.1429 N. Hence, this is the required solution.

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