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3 years ago

Photovoltic cells convert the energy of the sun directly to

Physics

1 answer:

sweet [91]3 years ago

5 0

Answer:

Photovoltic cells convert the energy of the sun directly to electricity

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If a bar magnet is broken into two pieces, each of the resulting pieces

victus00 [196]

They will become identical as if they were never broken

7 0

4 years ago

Select the correct answer. Five marbles roll down a ramp. Each marble reaches the bottom of the ramp at a speed of 3 meters/seco

MA_775_DIABLO [31]

Kinetic energy = (1/2) * mass * velocity

Marble 1 = (1/2) * 10 * 3 = 15 Joules

Marble 2 = 30 J

Marble 3 = 37.5 J

Marble 4 = 60 J

Marble 5 = 45 J

Marble 4 has the most kinetic energy - D.

4 0

3 years ago

Read 2 more answers

A particular coaxial cable is comprised of inner and outer conductors having radii 1 mm and 3 mm respectively, separated by air.

noname [10]

Answer:

The value is $\rho_s = 4.026 *10^{-6} \ C/m^2$

Explanation:

From the question we are told that

The radius of the inner conductor is $r_1 = 1 \ mm = 0.001 \ m$

The radius of the outer conductor is $r_2 = 3 \ mm = 0.003 \ m$

The potential at the outer conductor is $V = 1.5 kV = 1.5 *10^{3} \ V$

Generally the capacitance per length of the capacitor like set up of the two conductors is

$C= \frac{2 * \pi * \epsilon_o }{ ln [\frac{r_2}{r_1} ]}$

Here $\epsilon_o$ is the permitivity of free space with value $\epsilon_o = 8.85*10^{-12} C/(V \cdot m)$

=> $C= \frac{2 * 3.142 * 8.85*10^{-12} }{ ln [\frac{0.003}{0.001} ]}$

=> $C= 50.6 *10^{-12} \ F/m$

Generally given that the potential of the outer conductor with respect to the inner conductor is positive it then mean that the outer conductor is positively charge

Generally the line charge density of the outer conductor is mathematically represented as

$\rho_l = C * V$

=> $\rho_d = 50.6*10^{-12} * 1.5*10^{3}$

=> $\rho_d = 7.59*10^{-8} \ C/m$

Generally the surface charge density is mathematically represented as

$\rho_s = \frac{\rho_l }{2 \pi * r_2 }$ here $2 \pi r = (circumference \ of \ outer \ conductor )$

=> $\rho_s = \frac{7.59 *10^{-8} }{2* 3.142 * 0.003 }$

=> $\rho_s = 4.026 *10^{-6} \ C/m^2$

3 0

3 years ago

Plz help question in picture

Lostsunrise [7]

I think it's the last one

4 0

3 years ago

Read 2 more answers

A distant galaxy emits light that has a wavelength of 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 n

maksim [4K]

Answer:

A) receding from the earth

B) $3.078x10^6m/s$

Explanation:

A) receding from the earth

The wavelength went from 434.1nm to 438.6nm, there was an increase in wavelength (also knowecn as redshift due to the doppler efft), this increase is due to the fact that the source that emits the radiation (the distant galaxy) is moving away and therefore the light waves it emits are "stretched", causing us to see a wavelength greater than the original.