Total Number of cards = 4 + 6 = 10
Number of Football cards = 4
Number of Basketball cards = 6
Probability of choosing a football card = 4/10 = 0.4
Since this card is replaced, the total number of cards will remain the same.
Probability of selecting a basketball card = 6/10 = 0.6
Since, the two events are independent, the probability of selecting a football and a basketball card will be the product of two probabilities we calculated.
Thus, probability of selecting a football card and then a basketball card = 0.4 x 0.6 = 0.24
It would be 40,000 if you rounded up
Intersect with x axis indicates that x value would be Zero
Thus when x = 0
y would be
y = -18
Therefor intersection would be at (0,-18)
(5x-3)/4 = x/3 +1
5x-3 = 4x/3 +4
5x - 4x/3 = 7
(11/3)x = 7
x = 7/(11/3) = 21/11
