At a maximum level of loudness, the power output of a 75-piece orchestra radiated as sound is 72.0 W. What is the intensity of t
1 answer:
Answer:
<em> The intensity would be 0.01432 W/</em><em></em>
Explanation:
The sound intensity is the power that is transmitted by a sound wave per unit area.
Given that
Power output P of the 75-piece orchestra = 72.0 W
The listener's distance r = 20.0 m
The intensity of sound waves (I) can be obtained with the expression below;
I = P/A .............. 1
where P is the power
A is the area, in this case, at the distance r the sound is radiated through a sphere.
A = area of a sphere = 4π
putting it into equation 1, the intensity would be;
I = P/ 4π
Substituting our values we have;
I = 72.0 W / 4 π
I = 0.01432 W/
Therefore the intensity would be 0.01432 W/
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Answer:
and
Explanation:
According to Coulomb's law, the magnitude of force between two point object having change and
and by a dicstanced is
Where, is the permitivity of free space and
in SI unit.
Before dcollision:
Charges on both the sphere are and
, d=20cm=0.2m, and
N
So, from equation (i)
After dcollision: Each ephere have same charge, as at the time of collision there was contach and due to this charge get redistributed which made the charge density equal for both the sphere t. So, both have equal amount of charhe as both are identical.
Charges on both the sphere are mean of total charge, i.e
d=20cm=0.2m, and N
So, from equation (i)
As given that the force is repulsive, so both the sphere have the same nature of charge, either positive or negative, so, here take the magnitude of the charge.
The equation (ii) become:
From equation (iii)
So, the magnitude of initial charges on both the sphere are Coulombs
and
Colombs or
.
Considerion the nature of charges too,
and