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laiz [17]
4 years ago
12

a 2kg mass of copper falls from a height of 3m to an insulated floor. what is the maximum possible temperature increase of the c

opper?​
Physics
1 answer:
Rainbow [258]4 years ago
6 0

The maximum possible temperature increase of the copper is 0.076^{\circ}C

Explanation:

The energy gained by the mass of copper is equal to its change in gravitational potential energy, which is:

E=mg \Delta h

where

m = 2 kg is the mass of copper

g=9.8 m/s^2 is the acceleration of gravity

\Delta h= 3m is the change in height of the copper

Substituting,

E=(2)(9.8)(3)=58.8 J

The energy gained by the copper is related to its change in temperature by

E=mC_s \Delta T

where

m = 2 kg is the mass

C_s = 385 J/kg^{\circ} is the copper specific heat capacity

\Delta T is the change in temperature

And solving for \Delta T,

\Delta T = \frac{E}{mC_s}=\frac{58.8}{(2)(385)}=0.076^{\circ}C

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

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A 20.5 kg ball moving at 38.5 m/s on a horizontal, frictionless surface runs into a light spring of force
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7. These temperatures were recorded in Pasadena for a week in April. 87 85 80 78 83 86 90 Find each of these. (a) Mean (e) Range
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a) Mean = 84.14

b) Median = 85

c) Mode = no mode (since there is no variable that appears more than once in this dataset)

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The raw data to be processed is

87 85 80 78 83 86 90

a) Mean = (Σx)/N

The mean is the sum of variables divided by the number of variables

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b) Median is the number in the middle of the dataset when the variables are arranged in ascending or descending order.

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78, 80, 83, 85, 86, 87, 90

The number in the middle is the 4th number = 85

Median = 85

c) Mode is the variable that occurs the most in a distribution.

For this question, all of the variables occur only once, with no variable occurring more than once. Hence, there is no mode for this dataset.

d) Midrange is the arithmetic mean of the highest and lowest number in the dataset.

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Midrange = (Highest + Lowest)/2

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Range = 90 - 78 = 12

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Variance = [Σ(x - xbar)²/N]

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Σ(x - xbar)² = (78 - 84.14)² + (80 - 84.14)² + (83 - 84.14)² + (85 - 84.14)² + (86 - 84.14)² + (87 - 84.14)² + (90 - 84.14)² = 102.8572

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Variance = 14.69

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