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laiz [17]
3 years ago
12

a 2kg mass of copper falls from a height of 3m to an insulated floor. what is the maximum possible temperature increase of the c

opper?​
Physics
1 answer:
Rainbow [258]3 years ago
6 0

The maximum possible temperature increase of the copper is 0.076^{\circ}C

Explanation:

The energy gained by the mass of copper is equal to its change in gravitational potential energy, which is:

E=mg \Delta h

where

m = 2 kg is the mass of copper

g=9.8 m/s^2 is the acceleration of gravity

\Delta h= 3m is the change in height of the copper

Substituting,

E=(2)(9.8)(3)=58.8 J

The energy gained by the copper is related to its change in temperature by

E=mC_s \Delta T

where

m = 2 kg is the mass

C_s = 385 J/kg^{\circ} is the copper specific heat capacity

\Delta T is the change in temperature

And solving for \Delta T,

\Delta T = \frac{E}{mC_s}=\frac{58.8}{(2)(385)}=0.076^{\circ}C

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

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Question 14 (1 point)
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Answer:

car travel

precipitation

O temperature

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5 0
3 years ago
You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t
Sladkaya [172]

Answer:

0.767

Explanation:

The work done on the truck by the frictional drag force is given by

W=-Fd

where

F is the magnitude of the frictional force

d = 38.0 m is the maximum displacement allowed for the truck

The negative sign is due to the fact that the force of friction is opposite to the motion of the truck

The force of friction can also be written as:

F=\mu mg

where

\mu is the coefficient of kinetic friction between the truck and the lane

m is the mass of the truck

g is the acceleration of gravity

So we can rewrite the work done as

W=-\mu mg d (1)

According to the work-energy theorem, the work done by friction is equal to the change in kinetic energy of the truck:

W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2 (2)

where

v = 0 is the final velocity of the truck

u = 23.9 m/s is the initial velocity of the truck

By combining (1) and (2) we get

-\frac{1}{2}mu^2 = -\mu mg d

And solving for \mu, we find the minimum coefficient of kinetic friction able to stop the truck in a distance d:

\mu = \frac{u^2}{2gd}=\frac{23.9^2}{2(9.8)(38.0)}=0.767

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3 years ago
Two hockey pucks are sliding along the ice, towards the same goal, one directly in front of the other. The hockey puck in front
grandymaker [24]

Answer: A.9.2m/s

Explanation:

6 0
2 years ago
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