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faltersainse [42]
3 years ago
7

In what subject could we see cross cutting concepts

Physics
1 answer:
meriva3 years ago
4 0
A Framework for K–12 Science Education: Practices, Crosscutting Concepts, and Core Ideas (Framework) recommends science education in grades K–12 be built around three major dimensions: science and engineering practices, crosscutting concepts that unify the study of science and engineering through their common application across fields, and core ideas in the major disciplines of natural science.
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The carbon atom with 12 protons and 12 electrons has a charge of:
olga55 [171]

Answer:

Isotopes are the elements having the same atomic number i.e same number of protons which in turn is equal to same number of electrons. Number of protons and electrons are equal as the atom is electrically neutral. So, the only option is A.

I hope it helps you !

3 0
3 years ago
Calculate the momentum, A bald eagle with a mass of 26.4 kg and velocity of 15.6 m/s​
AveGali [126]

Answer:

<u>411.84 kg m/s</u>

Explanation:

Formula :

<u>Momentum = mass × velocity</u>

<u />

=========================================================

Given :

⇒ mass = 26.4 kg

⇒ velocity = 15.6 m/s

=========================================================

Solving :

⇒ Momentum = 26.4 × 15.6

⇒ Momentum = <u>411.84 kg m/s</u>

3 0
2 years ago
Why don't we feel pressure exerted by atmosphere?
ozzi
Crushing pressure. Human bodies are used to air pressure. The air pressure in our lungs, ears and stomachs is the same as the air pressure outside of our bodies, which ensures that we don't get crushed. Our bodies are also flexible enough to cope when the internal and external pressures aren't exactly the same.
6 0
4 years ago
An open pipe, 0.29 m long, vibrates in the second overtone with a frequency of 1,227 Hz. In this situation, the fundamental freq
Andru [333]

Answer:

f = 409 Hz

Explanation:

We have,

Length of the open organ pipe, l = 0.29 m

Frequency of vibration of second overtone, f_2 = 1227 Hz

It is required to find the fundamental frequency of the pipe. For the open organ pipe, the frequency of second overtone is given by :

f_2=\dfrac{3v}{2l}

v is speed of sound

Let f is the fundamental frequency. It is given by :

f=\dfrac{v}{2l}

The relation between f and f₂ can be written as :

f_2=3f\\\\f=\dfrac{f_2}{3}\\\\f=\dfrac{1227}{3}\\\\f=409\ Hz

So, the fundamental frequency of the pipe is 409 Hz.              

6 0
3 years ago
Which of the following objects does not orbit directly around the sun?
lys-0071 [83]
C. Moons because moons orbit planets not stars
3 0
3 years ago
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