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3 years ago

Need help with this!! Also, if possible, include a model! The question says you have too :(

Mathematics

2 answers:

soldier1979 [14.2K]3 years ago

7 0

11. 1 over 8
12.1 over 6
13.1 over 12

Sholpan [36]3 years ago

5 0

11 = 0.125
12 = 0.16
13 = 0.083
14 = 0.1

Read more about areas at:

brainly.com/question/76387

#SPJ1

8 0

2 years ago

What is the measure in radians for the central angle of a circle whose radius r = 4 cm, and intercepted arc length s = 1.2 cm? E

rodikova [14]

Answer:

17.1972degrees

Step-by-step explanation:

length of an arc = theta/360 * 2πr

Substitute the given angle;

1.2 = theta/360 * 2(3.14)(4)

1.2 = theta/360 * 25.12

1.2/25.12 = theta/360

0.04777 = theta/360

theta = 360 * .04777

theta = 17.1972

Hence the required angle is 17.1972degrees

6 0

3 years ago

Ace Cars says they will pay Jim a 10% commission on the sale price of each car. Budget Cars says they will pay him $500 per week

Arisa [49]

Answer:

$20,000

Step-by-step explanation:

You can quickly figure this by recognizing that the difference in commission must be the same as the base salary:

2.5%(car price) = $500

car price = $500/0.025 = $20,000

If you prefer, you can get there with equations.

At Job 1, the pay is ...

y = 10%×(car price)

At Job 2, the pay is ...

y = 7.5%×(car price)

Setting the equal (the two opportunities pay the same), we have ...

0.10(car price) = 500 +0.075(car price)

0.025(car price) = 500 . . . . . . . . subtract 0.075(car price)

car price = 500/0.025 = 20,000 . . . . divide by 0.025

Jim would have to sell a $20,000 car each week for the jobs to pay the same.

8 0

3 years ago

Derek found a function that approximately models the population of iguanas in a reptile garden, where x represents the number of

serious [3.7K]

Answer:

$i(x)=12 \times (1+\frac{0.9}{12})^{12x}$ and growth rate factor is 0.075

Step-by-step explanation:

The function that models the population of iguanas in a reptile garden is given by $i(x)=12 \times (1.9)^{x}$ , where x is the number of years.

Since, $i(x)=12 \times (1.9)^{x}$

i.e. $i(x)=12 \times (1+0.9)^{x}$ .

Therefore, the monthly growth rate function becomes,

i.e. $i(x)=12 \times (1+\frac{0.9}{12})^{x \times 12}$ .

i.e. $i(x)=12 \times (1+\frac{0.9}{12})^{12x}$ .

Hence, the monthly growth rate is i.e. $i(x)=12 \times (1+\frac{0.9}{12})^{12x}$ .

Also, the growth factor is given by $\frac{0.9}{12}$ = 0.075.

Thus, the growth factor to nearest thousandth place is 0.075.

4 0

3 years ago

What is the form of the Difference of Squares identity ? A. a ^ 2 - b ^ 2 = (a - b)(a - b) B. a ^ 2 + b ^ 2 = (a - b)(a - b); a

lozanna [386]

A^2 - b^2 = (a-b)(a+b)
To test it, expand the right hand side.

7 0

3 years ago