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ale4655 [162]
3 years ago
10

Please help me! It’s due soon! Please help!

Physics
1 answer:
Murrr4er [49]3 years ago
4 0

Answer:

do it yourself lazy h.e

Explanation:

kysc lazy btc

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Which of the following is not a component of a normal experiment?
MaRussiya [10]

Answer:

D. Validity group

Explanation:

A validity group is not necessarily a component of a normal experiment.

A normal experiment is made up of the dependent variables, independent variables, and most times the control group.

  • The dependent variable is one that relies on the outcome of the effect produced from the experimental design
  • The independent variable is the one that causes a desired effect under the study.
  • The control group is a group that does not receive any treatment nor attenuation of the conditions.
4 0
2 years ago
I don’t get how to answer the questions.
Dominik [7]
Write the answer below the question?
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2 years ago
You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body
stellarik [79]

A) The change in internal chemical energy is 1.15\cdot 10^7 J

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

P=Fv

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

P=(80)(8.0)=640 W

The energy output is related to the power by the equation

P=\frac{E}{t}

where:

P = 640 W is the power output

E is the energy output

t = 30 min \cdot 60 = 1800 s is the time elapsed

Solving for E,

E=Pt=(640)(1800)=1.15\cdot 10^6 J

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J

B)

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

E=1.15\cdot 10^7 J

Here we want to find the time t' needed to convert an amount of chemical energy of

E'=3.8\cdot 10^5 J

So we can setup the following proportion:

\frac{t}{E}=\frac{t'}{E'}

And solving for t',

t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min

Learn more about power and energy:

brainly.com/question/7956557

#LearnwithBrainly

3 0
2 years ago
Select the appropriate shape for the given volume form
vredina [299]
Fist one is a cylinder
the second, i believe is a sphere
the third is a rectangular prism
and the last is the same as the first, a cylinder
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2 years ago
A paper airplane used to study wing designs is an example of a ?
kow [346]
Model I'm guessing. Coz that's using an object to explain
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3 years ago
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